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Makovka662 [10]
3 years ago
11

What is a 15 yard gain 

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0
Are you by any chance referring to football? If you are, it is either a play in which by running or passing the offense moves down the field towards the opponent's endzone 15 yards, or it can be obtained by the defense committing an egregious penalty, such as a facemask, unsportsmanlike conduct, or unnecessary roughness.
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Is -2, 14 a solution to y=-5x+4 ?
larisa [96]

Answer:

yes

Step-by-step explanation:

y  = - 5x + 4

x = - 2

y = -5(-2) + 4     Two minuses make a plus

y = 10 + 4           Add

y = 14

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33, 25 , 19 , 8 , 3

Step-by-step explanation:

have a good day! :)

(sorry if it's wrong:( )

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82 Find the circumference
cupoosta [38]

Answer:

0.628 m (This is the correct answer but I cant find it in your options)

Step-by-step explanation:

Radius = 10 cm = 0.1 m

<u><em>Now, The circumference:</em></u>

=> Circumference = 2\pi r

=> C = 2(3.14)(0.1)

=> C = 0.628 m

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Find all x-intercepts and y-intercepts of the graph of the function . f(x) = - x ^ 3 + x ^ 2 + 12x If there is more than one ans
ololo11 [35]

Answer:

The y-intercept is (0,0)

The x-intercepts are (-3,0), (0,0), and (4,0)

Step-by-step explanation:

So we have the function:

f(x)=-x^3+x^2+12x

And we want to solve for the x- and y-intercepts.

Y)

To solve for the y-intercept, recall that the y-intercept is when the graph touches the y-axis. At that point, the x values is 0. Thus, to find the x-intercept, substitute 0 for x:

f(x)=-(0)^3+(0)^2+12(0)

Simplify:

f(x)=0

So, the y-intercept is (0,0)

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To solve for the x-intercept(s), set the function equal to 0 and solve for x:

0=-x^3+x^2+12x

First, factor out a negative x:

0=-x(x^2-x-12)

Factor within the parentheses:

0=-x(x-4)(x+3)

Zero Product Property:

-x=0\text{ or } x-4=0\text{ or } x+3=0

Divide by -1 on the first one. Add 4 on the second one. And subtract 3 on the right:

x=0\text{ or } x=4\text{ or } x=-3

So, our x-intercepts are:

(-3,0), (0,0), (4,0)

And we're done :)

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3 years ago
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