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ddd [48]
3 years ago
11

Solve by elimination and show all steps please 3x=2y-7, 2x-y=10

Mathematics
2 answers:
olasank [31]3 years ago
8 0

Answer:

if you download the app photomath it will help you

Step-by-step explanation:

I promise!

olga nikolaevna [1]3 years ago
7 0

Step-by-step explanation:

x=27 and y= 44

.......................

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Y=1/6x + 5 what is the answer
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X should equal  6y-30
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Find the slope and y-intercept of the line <br> 6x + 2y = –88
ira [324]
Y=mx+b
6x+2y=-88
2y=-88-6x
y=-44-3x
y=-3x-44
m is the slope
b is the y-intercept
4 0
3 years ago
The width of a rectangular window is 24 inches. the area is 624 square inches. What is the length?
Feliz [49]

Answer:

Using the formula

A=wl

Solving forl

l=A

w=624

24=26in

8 0
2 years ago
Read 2 more answers
A person purchased 10 items to donate to a school. They bought backpacks that cost $25.75 each and notebooks that cost $4.25 eac
krek1111 [17]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
In a study of the effect of college student employment on academic performance, the following summary statistics for GPA were re
11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μemployed(μ1) be the sample mean of students who are employed and μnot employed(μ2) be the sample mean of students who are not employed

The random variable is μ1 - μ2 = difference in the mean of the employed and unemployed students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(μ1 - μ2)/√(s1²/n1 + s2²/n2)

From the information given,

μ1 = 3.22

μ2 = 3.33

s1 = 0.475

s2 = 0.524

n1 = 172

n2 = 116

t = (3.22 - 3.33)/√(0.475²/172 + 0.524²/116)

t = - 1.81

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.475²/172 + 0.524²/116]²/[(1/172 - 1)(0.475²/172)² + (1/116 - 1)(0.524²/116)²] = 0.00001353363/0.00000005878

df = 230

We would determine the probability value from the t test calculator. It becomes

p value = 0.036

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis.

Therefore, at a 5% significant level, this information support the hypothesis that for students at this university, those who are not employed have a higher mean GPA than those who are employed

3 0
3 years ago
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