the equation of line that is perpendicular to 2x+y=3 & passes through points (2,-5) is:
Step-by-step explanation:
Given equation of line is:
Let m1 be the slope of given line and
m2 be the slope of line perpendicular to given line
The slope of first line will be (The coefficient of x)
m1 = -2
We know that the product of slopes of two perpendicular lines is -1
So,
slope-intercept form is:
Putting the value of slope we get
Putting the point in the equation
Putting the value of b
Hence,
the equation of line that is perpendicular to 2x+y=3 & passes through points (2,-5) is:
Keywords: slope, Equation of line
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Answer:
T = 2.797
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.797