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Sindrei [870]
4 years ago
11

A solid sphere and a solid cylinder, both uniform and of the same mass and radius, roll without slipping at the same forward spe

ed. It is correct to say that the total kinetic energy of the solid sphere is
less than the total kinetic energy of the cylinder
Physics
1 answer:
Veseljchak [2.6K]4 years ago
7 0

Answer:

It is correct to say that the total kinetic energy of the solid sphere is

less than the total kinetic energy of the cylinder

Explanation:

The correct option is ; answer is Option ( A ) -  is less than the total kinetic energy of the cylinder because moment of inertia of solid cylinder ( 0.5 mr² ) is higher than moment of inertia of sphere ( 0.4 mr² ), as such, total energy of sphere will be less than the solid cylinder.

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6. For a cell to produce a current, the
Reil [10]

Answer:

for a cell to produce a current the cell electrodes of the cell must have a potential difference option A is the correct answer

6 0
2 years ago
Read 2 more answers
a diver on a board 7.5m above the water walks off the end with a horizontal velocity of 2.3 m/s when they hit the surface of the
m_a_m_a [10]

Answer:

2.846m

Explanation:

The diver is performing projectile motion.

To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)

x(initial) = 0

x(final) = ?

v(initial) = 2.3 m/s

we don't know t

To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)

- 9.8 in the acceleration in the y dir.

y(final) = 0

y(initial) = 7.5

v(initial in the y dir.) = 0

If we solve for t we get: t = 1.237s

Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)

x(final) = 2.3*1.237 + 0

x(final) = 2.846m

6 0
3 years ago
An engine absorbs 1.69 kJ from a hot reservoir at 277°C and expels 1.25 kJ to a cold reservoir at 27°C in each cycle.
Anna35 [415]

Answer

Given,

Energy absorbed, Q_H = 1.69\ kJ

Energy expels,Q_C =  1.25\ kJ

Temperature of cold reservoir, T = 27°C

a) Efficiency of engine

 \eta = \dfrac{Q_H - Q_C}{Q_H}\times 100

 \eta = \dfrac{1.69 - 1.25}{1.69}\times 100

\eta =26.03 %

b) Work done by the engine

 W = Q_H- Q_C

 W =1.69 - 1.25

 W = 0.44\ kJ

c) Power output

     t = 0.296 s

   P = \dfrac{W}{t}

   P = \dfrac{0.44}{0.296}

   P = 1.486\ kW

8 0
3 years ago
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Two objects have a certain gravitational force between them. What would happen if the mass of one of the objects suddenly increa
ludmilkaskok [199]
Your answer would be A.
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