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Helga [31]
3 years ago
6

Raindrops are falling straight down at 11 m/s when suddenly the wind starts blowing horizontally at a brisk 5.0 m/s. From your p

oint of view, the rain is now coming down at an angle. What is the angle, relative to the vertical?
Physics
1 answer:
Bumek [7]3 years ago
8 0

Answer: 24.4 degrees to the vertical

Explanation:

Vertical component of raindrop speed = 11m/s

Horizontal component of wind = 5m/s

In this case, all we have to do is to use trigonometric ratios of angles to sides as in a triangle

Doing this, we see that

tan (theta) = 5/11

(Where theta is the angle made with the vertical by the rain after impact)

Tan being opposite/adjacent

Arc sin (5/11) gives us 24.44 degrees to the vertical

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A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3 km/h.
Amanda [17]

Answer:

F_{1}=\frac{1}{5}F_{2}  or  F_{2}=5F_{1}

In other words, F_{1} is one fifth of F_{2} or F_{2} is five times as big as F_{1}

Explanation:

In order to solve this problem we must start by sketching the situation (refer to the attached picture).

When the ship is pulled only by force 1, it will change its speed by 3km/hr in 10 seconds. So in order to use these values we need to either turn the km/hr in km/s or turn the seconds to hours. Let's turn the seconds to hours:

10s*\frac{1hr}{3600s}=\frac{1}{360} hr

so we can now use the acceleration formula to find the acceleration of the boat so we get:

a=\frac{\Delta v}{\Delta t}

which will give us an accceleration of:

a=\frac{3km/hr}{\frac{1}{360}hr}=1080km/hr^{2}

once we got the acceleration we can for sure say taht:

F_{1}=ma=m*1080\frac{km}{hr^{2}}

Now, if we take a look at the second drawing we can see that the resultant force applied to the boat is found by adding the two forces, force one and force two, so we get:

F_{1}+F_{2}=ma

in this case the acceleration changes because the change in velocity is of 18km/hr in the same 10 seconds, so we get that:

a=\frac{\Delta v}{\Delta t}

a=\frac{18km/hr}{\frac{1}{360}hr}=6480km/hr^{2}

so we can say that:

F_{1}+F_{2}=m*6480km/hr^{2}

we can substitute the first force into this equation so we get:

m*1080km/hr^{2}+F_{2}=m*6480km/hr^{2}

and solve for the second force, so we get:

F_{2}=m*6480km/hr^{2}-m*1080km/hr^{2}

which yields:

F_{2}=m*5400km/hr^{2}

Now we can compare theh two forces, force 1 and force 2 by dividing them:

\frac{F_{1}}{F_{2}}=\frac{m*1080km/hr^{2}}{m*5400km/hr^{2}}

which yields:

\frac{F_{1}}{F_{2}}=\frac{1}{5}

when solving for the first force we get:

F_{1}=\frac{1}{5}F_{2}

which tells us that the second force is one fifth of the first force.

and when solving for the second force we get that:

F_{2}=5F_{1}

which means that the second force is 5 times as big as the first force.

8 0
3 years ago
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Naily [24]

Answer:

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Explanation:

5 0
3 years ago
Identify the areas on the image where the force of repulsion is the least.
ArbitrLikvidat [17]

Each magnet has a north pole and a south pole. We know that, from having played with bar magnets in our childhood, that a magnet's north pole will repel another magnet's north pole and attract its south pole.

From this diagram it is easy to see that the two lower bar magnets not only repel each other, but they are quite attracted to each other since their north and south poles are close together.

Therefore the region between the lower two magnets has the least force of repulsion.

3 0
3 years ago
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Long wavelength corresponds to having _________frequency
Vladimir [108]
Long wavelength corresponds to having lower frequency
4 0
3 years ago
Read 2 more answers
a 15 kg tv sots on a shelf at a height of 0.3 m. how much gravitational potential energy is added to the television when it is l
nata0808 [166]
Gravitational potential energy can be described as m*g*h (mass times gravity times height).

Originally,
15kg * 9.8m/s^2 *0.3 m = 44.1 kg*m^2/s^2 = 44.1 Joules.

After it is moved to a 1m shelf:
15kg * 9.8m/s * 1 = 147 kg*m^2/s^2= 147 Joules.

To find how much energy was added, we subtract final energy from initial energy:

147 J - 44.1 J = 102.9 Joules.
6 0
3 years ago
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