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lora16 [44]
3 years ago
14

1. In ABC, C is a right angle and BC = 11. If B = 30°, find AC. (1 point)

Mathematics
2 answers:
faltersainse [42]3 years ago
7 0

Answer:

AC=\frac{11\sqrt{3}}{3}

Step-by-step explanation:

Given that triangle ABC is a right angle triangle. Where angle C is a right angle. Also we have been given that BC = 11, B = 30°. Now we need to find the value of AC.

Apply formula:

\tan\left(\theta\right)=\frac{opposite}{adjacent}

\tan\left(B\right)=\frac{AC}{BC}

\tan\left(30^o\right)=\frac{AC}{11}

\frac{1}{\sqrt{3}}=\frac{AC}{11}

\frac{11}{\sqrt{3}}=AC

AC=\frac{11}{\sqrt{3}}

or

AC=\frac{11}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}

or

AC=\frac{11\sqrt{3}}{3}

Hence final answer is AC=\frac{11\sqrt{3}}{3}.

Mademuasel [1]3 years ago
7 0
The answer is the first one (A)
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