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krek1111 [17]
4 years ago
15

Based on all student records at Camford University, students spend an average of 5.30 hours per week playing organized sports. T

he population’s standard deviation is 3.20 hours per week. Based on a sample of 64 students, Healthy Lifestyles Incorporated (HLI) would like to apply the central limit theorem to make various estimates. Compute the standard error of the sample mean. (Round your answer to 2 decimal places.)
Mathematics
1 answer:
mina [271]4 years ago
8 0

Answer:

The standard error of the sample mean is \sigma_{\= x } = 0.40

Step-by-step explanation:

From the question we are told that

     The population mean is  \mu  =  5.30 \ hours

     The population standard deviation is \sigma =  3.20 \  hours

      The sample size is  n =  64

Generally the standard error of the sample mean is mathematically represented as

               \sigma_{\= x } =  \frac{\sigma}{\sqrt{n} }

substituting values

                \sigma_{\= x } =  \frac{3.20}{\sqrt{64} }

                \sigma_{\= x } = 0.40

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