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lutik1710 [3]
3 years ago
7

Solve the following system of equations . Plot the solution to the system on the provided graph

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

(6, -3)

Step-by-step explanation:

I will solve this system using elimination.

[tex]\left \{ {{-x+2y=-12} \atop {2x+3y=3}} \right.[/tex]

I will multiply -x+2y=-12 by 2 so that -x becomes -2x.

2(-x + 2y = -12)

Distribute.

-2x + 4y = -24

Now subtract this from the other equation.

2x + 3y = 3

<u>-2x + 4y = -24</u>

        7y  =  -21

Divide both sides by 7.

y = -3

Now that we have the value of y, plug it into the original equation.

-x + 2(-3) = -12

Simplify.

-x - 6 = -12

Add 6 to both sides.

-x = -6

Divide both sides by -1.

x = 6

(6, -3)

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AlekseyPX

Given:

Right triangle XYZ has right angle Z.

\sin(x)=\dfrac{12}{13}

To find:

The value of \cos x.

Solution:

We know that,

\sin^2(x)+\cos^2(x)=1

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\cos(x)=\pm\sqrt{1-\sin^2x}

For a triangle, all trigonometric ratios are positive. So,

\cos(x)=\sqrt{1-\sin^2x}

It is given that \sin(x)=\dfrac{12}{13}. After substituting this value in the above equation, we get

\cos(x)=\sqrt{1-(\dfrac{12}{13})^2}

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\cos(x)=\sqrt{\dfrac{169-144}{169}}

\cos(x)=\sqrt{\dfrac{25}{169}}

On further simplification, we get

\cos(x)=\dfrac{\sqrt{25}}{\sqrt{169}}

\cos(x)=\dfrac{5}{13}

Therefore, the required value is \cos(x)=\dfrac{5}{13}.

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3 years ago
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