Question

For a more difficult training session, the mass to be pushed is increased to 160 kg. If the players still push with a force of 150 N, what is the acceleration of the objection?
Use Newton's law:
F=ma
150 N=

Answer 1

As you already written, you have to use Newton's law

$F=ma$

where F is the force, m is the mass, and a is the acceleration.

You already know the mass and the force, so you have to solve the equality for the acceleration:

$a = \dfrac{F}{m}$

plug the given values:

$a = \dfrac{150}{160} = \dfrac{15}{16} = 0.9375$