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Hoochie [10]
3 years ago
5

How is a linear function different from a linear equation

Mathematics
1 answer:
adell [148]3 years ago
7 0

Answer:

Linear function= in a linear function  a graph must have both the linear equation [straight lines] and an equation [x-yalue and y-value]

----------------------

Linear equation= produce strainght lines when you graph it out

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One leg of a right triangle measures 6 inches. The remaining leg measures 6 StartRoot 3 EndRoot inches. What is the measure of t
Usimov [2.4K]

Answer:

∅ = 30°

Step-by-step explanation:

given data

side 1 = 6 inches

side 2 = 6\sqrt{3}  inches

to find out

angle opposite the leg that is 6 inches long

solution

we  will use pythagoras theorem that is express as

hypotenuse² = perpendicular²   + base²     .......................1

put here value and we get  hypotenuse

hypotenuse² = 6² + (  )²

solve it we get

hypotenuse²  = 144

hypotenuse = 12 inches  

now we apply here sin∅ that is

sin∅ = \frac{perpendicular}{hypotenuse}     ................2

put here value and we get

put here value and we get

sin∅ = \frac{6}{12}  

∅ = sin^{-1}(0.5)  

solve it we get

∅ = 30°

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3 years ago
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Carlos is baking banana bread. He uses 3/8 cup of brown sugar in one loaf. He is making six loaves of banana bread. How much bro
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2 cups of brown sugar
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7. A line in the Cartesian plane passes through the points (1, 3) and (5, 4). What is the slope of the line? A. 1/4 B. –4/1 C. 4
mojhsa [17]

A

to calculate the slope m , use the ' gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 3) and (x₂, y₂ ) = (5, 4)

m = \frac{4 - 3}{5 - 1} = \frac{1}{4} → A


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Find all n∈IN such that the number of digits of n equal to n
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Note that \log_{10}1=0, \log_{10}10=1, \log_{10}100=2, and so on. The function \log_{10}x is continuous and increasing for all x>0, so when 1, we have 0; when 10, 1; and so on.

This means

\lfloor\log_{10}x\rfloor=\begin{cases}0&\text{for }1\le x

which means we can capture the number of digits of n\in\mathbb N with the function \lfloor\log_{10}n\rfloor+1.

So the problem is the same as finding positive integer solutions to

\lfloor\log_{10}n\rfloor+1=n

We know that n=1 has one digit, so clearly this must be a solution. We need to show that this is the only solution.

Recall that \dfrac{\mathrm d}{\mathrm dx}[\log_{10}x+1]=\dfrac1{\ln10\,x}, while \dfrac{\mathrm d}{\mathrm dx}[x]=1. This means \log_{10}x increases at a much slower rate than x as x\to\infty. We know the two functions intersect when x=1. Therefore it's clear that x>\log_{10}x+1 for all x>1.

Now, it's always the case that \lfloor f(x)\rfloor\le f(x), so we're essentially done:

x>\log_{10}x+1\ge\lfloor\log_{10}x\rfloor+1

which means there are no other solutions than n=1.
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