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Genrish500 [490]
3 years ago
14

Everybody at a company is assigned a unique 9 digit ID. How many unique IDs exist?

Computers and Technology
1 answer:
timama [110]3 years ago
3 0

Answer:

3,265,920 unique ID exist.

Explanation:

The nine digits are from 0 to 9, there are ten bits from 0 -9,

0, 1, 2, 3, 4, 5, 6, 7, 8, 9

The first is select from the highest bit (9), and the second is selected at random from 0 - 9, the third bit to the last must be unique and different from each other;

number of unique IDs = 9 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2

Multiplying the nine bits of unique IDs = 3,265,920.

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sammy [17]

Answer:

Explanation:

try numpy:

import numpy as np

print(np.average([3, 4, 8]))

output:

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Under which of the following conditions will evaluating this boolean expression
zzz [600]
1.) 
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>

<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>

<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>

<span>a.) (i <= n) || (i >= n) </span>

<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>

<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>

<span>This means that both of these terms are true. We substitute. </span>

<span>((i <= n) && true) || (((i >= n) && true)) </span>

<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>

<span>(i <= n) || (i >= n) </span>

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3 0
3 years ago
____ is suitable for what are called "high-volume service control applications" such as dial-in access to a corporate network.
Levart [38]

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The authentication mechanism start by user who sends a message to the RADIUS server. Then the RADIUS server upon receiving the message accept or denies it. It accepts if the client is configured to the server.

A large amount of additional information can be sent by the RADIUS server in its Access-Accept messages with users so we can say that RADIUS is uitable for what are called "high-volume service control applications" such as dial-in access to a corporate network.

3 0
3 years ago
Select the steps for adding artwork into a placeholder on a presentation slide
Sloan [31]

Answer:

   Open the presentation that you want to add a slide to.

   In the pane that contains the Outline and Slides tabs, click Slides, and then click where you want to add a slide.

Explanation:

6 0
4 years ago
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