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mixas84 [53]
4 years ago
10

Task 2 Design a 1st order low-pass filter with cutoff frequency 1kHz, 1) with roll-off and 2) without roll-off. For each filter,

a) Provide the transfer function. b) Plot the step response of these filters. c) Plot the Bode frequency response of these filters. d) Compare the step and frequency responses of these two filters. e) Include the MATLAB code.

Computers and Technology
1 answer:
miskamm [114]4 years ago
6 0

You can get complete answer in attached document.please have a look.

Explanation:

(2) Without rolloff, as given fc =1kHz Let us assume it is a first order RC filter ats transfer function is H(s)-RC RC withou

Then the transfer function becom

and step response is flat zero for without rolloff..

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Answer:

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dimes = int((cents - 100*dollars- 25*quarters)/10)

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

if not(dollars == 0):

   if dollars > 1:

       print(str(dollars)+" dollars")

   else:

       print(str(dollars)+" dollar")

if not(quarters == 0):

   if quarters > 1:

       print(str(quarters)+" quarters")

   else:

       print(str(quarters)+" quarter")

if not(dimes == 0):

   if dimes > 1:

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   else:

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if not(nickels == 0):

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   else:

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if not(pennies == 0):

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Explanation:

A prompt to input amount in cents

cents = int(input("Cents: "))

Convert cents to dollars

dollars = int(cents/100)

Convert the remaining cents to quarters

quarters = int((cents - 100*dollars)/25)

Convert the remaining cents to dimes

dimes = int((cents - 100*dollars- 25*quarters)/10)

Convert the remaining cents to nickels

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

Convert the remaining cents to pennies

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

This checks if dollars is not 0

<em>if not(dollars == 0):</em>

If greater than 1, it prints dollars (plural)

<em>    if dollars > 1:</em>

<em>        print(str(dollars)+" dollars")</em>

Otherwise, prints dollar (singular)

<em>    else:</em>

<em>        print(str(dollars)+" dollar")</em>

This checks if quarters is not 0

<em>if not(quarters == 0):</em>

If greater than 1, it prints quarters (plural)

<em>    if quarters > 1:</em>

<em>        print(str(quarters)+" quarters")</em>

Otherwise, prints quarter (singular)

<em>    else:</em>

<em>        print(str(quarters)+" quarter")</em>

This checks if dimes is not 0

<em>if not(dimes == 0):</em>

If greater than 1, it prints dimes (plural)

<em>    if dimes > 1:</em>

<em>        print(str(dimes)+" dimes")</em>

Otherwise, prints dime (singular)

<em>    else:</em>

<em>        print(str(dimes)+" dime")</em>

This checks if nickels is not 0

<em>if not(nickels == 0):</em>

If greater than 1, it prints nickels (plural)

<em>    if nickels > 1:</em>

<em>        print(str(nickels)+" nickels")</em>

Otherwise, prints nickel (singular)

<em>    else:</em>

<em>        print(str(nickels)+" nickel")</em>

This checks if pennies is not 0

<em>if not(pennies == 0):</em>

If greater than 1, it prints pennies (plural)

<em>    if pennies > 1:</em>

<em>        print(str(pennies)+" pennies")</em>

Otherwise, prints penny (singular)

<em>    else:</em>

<em>        print(str(pennies)+" penny")</em>

<em>    </em>

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