1.78L x (3.00M/1L) = 5.34
The Kelvin Scale is used, so the answer is temperature :)
Tt is the genotype that will appear in boxes two and three.
If you look at the column and row that intersect to form boxes two and three, you will see that they are T and t. That is the best way I can describe it, sorry if it’s confusing.
Answer: There are 1.78 moles in 40.0 L of He gas at STP
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (STP)
V = Volume of gas = 40.0 L
n = number of moles = ?
R = gas constant =
T =temperature =
(STP)
Thus there are 1.78 moles in 40.0 L of He gas at STP
Answer:

Explanation:
The relation between Kp and Kc is given below:
Where,
Kp is the pressure equilibrium constant
Kc is the molar equilibrium constant
R is gas constant
T is the temperature in Kelvins
Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
For the first equilibrium reaction:
Given: Kc = 0.140
Temperature = 1778 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (1778 + 273.15) K = 2051.15 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (3+1)-(2) = 2
Thus, Kp is:
