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Wittaler [7]
3 years ago
6

What happens to visible light as it passes through a prism that produces colored light?

Chemistry
2 answers:
allochka39001 [22]3 years ago
8 0
You get the Dark side of the moon album art..jk

On passage through the prism the light is seperated into colors and it is known as dispersion 
Hope I helped :)
have a good one
xz_007 [3.2K]3 years ago
4 0
When light passes through a prism it causes a source of light which can also have a connection with what we know as a rainbow. <span>This also affectsthe number of waves </span>produced<span> each second</span>
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How many moles are there in a 3.00M solution when you have 1.78L
frozen [14]
1.78L x (3.00M/1L) = 5.34
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3 years ago
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Shalnov [3]
The Kelvin Scale is used, so the answer is temperature :)
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3 years ago
What do genotype will appear in boxes 2 and 3?
VMariaS [17]
Tt is the genotype that will appear in boxes two and three.

If you look at the column and row that intersect to form boxes two and three, you will see that they are T and t. That is the best way I can describe it, sorry if it’s confusing.
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3 years ago
Read 2 more answers
What is the number of moles in 40.0 L of He gas at STP?
Alla [95]

Answer: There are 1.78 moles in 40.0 L of He gas at STP

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (STP)

V = Volume of gas = 40.0  L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K   (STP)

n=\frac{PV}{RT}

n=\frac{1atm\times 40.0L}{0.0821Latm/K mol\times 273K}=1.78moles

Thus there are 1.78 moles in 40.0 L of He gas at STP

8 0
3 years ago
For chemical reactions involving ideal gases, the equilibrium constant K can be expressed either in terms of the concentrations
miskamm [114]

Answer:

K_p= 3966.01

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2CH_4_{(g)}\rightleftharpoons C_2H_2_{(g)}+3H_2_{(g)}

Given: Kc = 0.140

Temperature = 1778 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (1778 + 273.15) K = 2051.15 K  

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (3+1)-(2) = 2  

Thus, Kp is:

K_p= 0.140\times (0.082057\times 2051.15)^{2}

K_p= 3966.01

6 0
3 years ago
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