Answer:
<u>Optical purity = 76.9231 %</u>
<u>Specific rotation of mixture = - 97.6923 °</u>
Explanation:
The mass of the racemic mixture = 3 g
It means it contains R enantiomer = 1.5 g
S enantiomer = 1.5 g
Amount of Pure R = 10 g
Total R = 11.5 g
Total volume = 500 mL + 500 mL = 1000 mL = 1 L
[R] = 11.5 g/L
[S] = 1.5 g/L
Enantiomeric excess = 
= 
= 76.9231 %
<u>Optical purity = 76.9231 %</u>
Also,
Optical purity = 
Optical rotation of pure enantiomer = −127 °
<u>Specific rotation of mixture = - 97.6923 °</u>
Answer:
V₂ = 530.5 mL
Explanation:
Given data:
Initial temperature = 20.0°C
Final temperature = 40.0 °C
Final volume = 585 mL
Initial volume = ?
Solution:
Initial temperature = 20.0°C (20+273 = 293 K)
Final temperature = 40.0 °C (40+273 = 323 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₁ = V₂T₁ /T₂
V₂ = 585 mL × 293 K / 323 K
V₂ = 171405 mL.K / 323 K
V₂ = 530.5 mL
<h2>Answer -
0.73%</h2>
14.6 .2
=
100 x
(Above is proportions I used to get the answer)
x = 0.73% which is the answer.
Answer is: <span>the volume of water after the solid is added</span> is 4.5 ml.
d(gold) = 8.0 g/cm³; density of gold.
m(gold) = 4 g; mass of gold.
V(gold) = m(gold) ÷ d(gold); volume of gold.
V(gold) = 4 g ÷ 8 g/cm³.
V(gold) = 0.5 cm³ = 0.5 ml.
V(water) = 4.00 ml = 4.00 cm³.
V(flask) = V(gold) + V(water).
V(flask) = 0.5 cm³ + 4 cm³.V = 4.5 cm³.
