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Lena [83]
3 years ago
9

Someone please help! I will give Brainliest to who answers the best! Write an explanation of how mass determines (or affects) th

e force of gravity. If you answer nothing important or related to the answer just for the points then I will report you!

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
8 0
Gravity is the force of motion pulling down objects to the ground. If there was no gravity, everyone would walking as if they were on the moon.


Mass is what gravity needs. If an object has a little amount of mass, gravity will be able to easily bring it to the ground.


If an object has a very huge amount of mass, gravity will still be able to bring it to the ground but it will be hard.


For example: An airplane has a HUGE amount of mass. Gravity pulls it down but the airplane needs to be steering up in order for it to be straight. Gravity is applied on the airplane when it is landing.

BUT..... if a table is in the way of an object it depends if it will fall down to the ground or stay on the table.

If an object has little mass and a table is in the way of gravity pulling it down to the ground, the object will stay on the table. Like a plate of food on a table.

If an object has a very big amount of mass and a table is in the way of gravity pulling it to the ground, the object will break the object and make it's make to the ground. That is mostly why most of the time people have very strong tables/ anything to hold a heavy object.  


Another example is if you're lifting weights and you have little amount of mass, you're most likely to get the little sized weight. It depend on you mass.


Here are some pictures I included here as well of Mass and gravity.

Glad to help! :) :D

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A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur
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Answer:

12.8 g of O_{2} must be withdrawn from tank

Explanation:

Let's assume O_{2} gas inside tank behaves ideally.

According to ideal gas equation- PV=nRT

where P is pressure of O_{2}, V is volume of O_{2}, n is number of moles of O_{2}, R is gas constant and T is temperature in kelvin scale.

We can also write, \frac{V}{RT}=\frac{n}{P}

Here V, T and R are constants.

So, \frac{n}{P} ratio will also be constant before and after removal of O_{2} from tank

Hence, \frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}

Here, \frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm} and P_{after}=17atm

So, n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol

So, moles of O_{2} must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of O_{2} = 32 g/mol

So, mass of O_{2} must be withdrawn = (32\times 0.40)g=12.8g

7 0
3 years ago
Calcium Carbide (CaC2) is an unusual substance that contains a carbon anion (C2 2- ). The reaction with water involves several s
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The question is incomplete. The complete question is:

Calcium Carbide (CaC₂) is an unusual substance that contains a carbon anion (C₂²⁻). The reaction with water involves several steps that occur in rapid succession. CaC2 is a salt (notice that its name is similar to sodium chloride). When a salt dissolves in water, ions leave the crystal lattice and enter the aqueous (aq) solution. Write the relevant balanced chemical equation for the dissolution of CaC₂, in water.

Answer:

CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(aq)

Explanation:

When a salt dissolves in water, it dissociates in its ions. In the Calcium Carbide, the cation is Ca⁺² and the anion is C₂²⁻, so the reaction is:

CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(aq)

The base Ca(OH)₂ is soluble, so it will dissociate at Ca⁺ and OH⁻, but the C₂H₂ is stable and doesn't dissociate in the solution.

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