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Ierofanga [76]
3 years ago
8

If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol

Chemistry
1 answer:
igomit [66]3 years ago
5 0

Answer:

\Delta _RH=4x10^{-3}\frac{kJ}{mol}

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}

Best regards.

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Naddik [55]

The excerpt from an essay about higher education that most clearly shows an example of logos is:

  • Option d:  Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.

<h3>What is Logos?</h3>

The Logos Definition is one that is often argued by a lot of people as people tends to appeal to others emotions and some other times, people do appeal to one's' ethics or morals.

The term logos is a term that connote the use of logic. It also includes the use of deductive reasoning to get to a conclusion.

The excerpt from an essay about higher education that most clearly shows an example of logos is:

  • Option d:  Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.

Option d is correct because it shows the cause and its effect.

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8 0
2 years ago
Write a general word equation for a neutralization reaction.
xenn [34]
Hydrochloric acid + Sodium hydroxide =Sodium chloride +water
8 0
3 years ago
The pKa of lactic acid is 3.9. A lactate buffer will be useful from pH values ________. The pKa of lactic acid is 3.9. A lactate
Vedmedyk [2.9K]

Answer:

Explanation:

The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.  

This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since  buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .

From the Henderson-Hasselbach equation we have that

pH = pKa + log [A⁻]/[HA]

thus

0.1 ≤  [A⁻]/[HA] ≤ 10

Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.

Now we are equipped to answer our question:

pH range = 3.9 +/- 1 = 2.9 through 4.9

7 0
3 years ago
What climate zone is asia?
dolphi86 [110]

Answer:

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Explanation:

:) hope this helps

6 0
2 years ago
Read 2 more answers
6.0 mol Al reacts with 4.0 mol O2 to form Al2O3.
Tema [17]

Answer:

3.0 moles Al₂O₃

Explanation:

We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.

4 Al + 3 O₂ -----> 2 Al₂O₃

6.0 moles Al            2 moles Al₂O₃
----------------------  x  -------------------------  =  3.0 moles Al₂O₃
                                    4 moles Al

4.0 moles O₂           2 moles Al₂O₃
----------------------  x  -------------------------  =  2.7 moles Al₂O₃
                                    3 moles O₂

As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.

However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.

6 0
1 year ago
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