What is the volume of a cone (in cubic inches) of radius 5 inches and height 3
1 answer:
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The bridge attached is drawn according to given dimensions, and it doesn't look right. Please double check the given dimensions.
Calculations:
Horizontal part of bottom chord below the 70 degree triangle
= 15.1*cos(70) = 5.16 (which is a major prt of the 6.3 units.
Height of vertical pieces DF and EH
= 15.1*sin(70) = 14.19
Note that structurally, DF and EH do not help in reducing stress on the bridge, since they are perpendicular to the bottom chord.
Therefore
angle B = atan(14.19/(6.3-5.16))=85.41 degrees
I believe the whole geometry does not look right, esthetically, and structurally, since the compression members are much longer than the tension members in the middle. (The vertical members carry no force.)
If you can review the input data, or post a new question, I will be glad to help.
Calculations:
Horizontal part of bottom chord below the 70 degree triangle
= 15.1*cos(70) = 5.16 (which is a major prt of the 6.3 units.
Height of vertical pieces DF and EH
= 15.1*sin(70) = 14.19
Note that structurally, DF and EH do not help in reducing stress on the bridge, since they are perpendicular to the bottom chord.
Therefore
angle B = atan(14.19/(6.3-5.16))=85.41 degrees
I believe the whole geometry does not look right, esthetically, and structurally, since the compression members are much longer than the tension members in the middle. (The vertical members carry no force.)
If you can review the input data, or post a new question, I will be glad to help.
Answer:
Step-by-step explanation:
We have the exponential function of the form:
And it goes through the points (0, 13) and (3, 832).
Hence, when we substitute in 0 for x, we should get 13 for y. Therefore:
Since anything to the zeroth power is 1, this yields:
So, we determined that the value of a is 13.
So, our function is now:
We will need to determine b. We know that y equals 832 when x is 3. Hence:
Divide both sides by 13:
Take the cube root of both sides:
Hence, our b value is 4.
Therefore, our entire equation is: