1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
il63 [147K]
3 years ago
10

Sentences How to calculate the orbital period

Physics
1 answer:
DaniilM [7]3 years ago
5 0

Use this formula where:

∝ is the average distance between the centers of the two bodies

G is the gravitational constant

M1 and M2 are masses of the parent body and the orbiting body respectively.


You might be interested in
1. Oil or water clinging to a surface of a jar is an example of:
Oduvanchick [21]
1) B- adhesion

3) c- they increase friction
8 0
3 years ago
A diver of mass 101 kg jumps upward off a diving board and into the water. The diving board is 6 m above the water.
goblinko [34]

PART a)

As we know that kinetic energy is given by

K = \frac{1}{2} mv^2

here we know that

m = 101 kg

v = 1.2 m/s

now from above equation

K = \frac{1}{2}(101)(1.2)^2

K = 72.72 J

Part B)

As we know that gravitational potential energy is given by

U = mgh

Now we know that here there is no loss in energy due to friction

So she will gain its potential energy by the loss of kinetic energy

So her gain in potential energy at the top = initial kinetic energy

So gain in potential energy = 72.72 J

PART C)

So here we can use the formula of potential energy in order to find the maximum height

U = mgh

72.72 = 101(9.81)h

h = 0.0735 m

so she will be 7.35 cm above the initial height

PART D)

By energy conservation we can find the final speed when she hit the water

So by energy conservation law we know that

KE_i + U_i = KE_f

72.72 + 101(9.8)6 = \frac{1}{2}(101)v_f^2

now we have

v_f^2 = 119.04

v_f = 10.91 m/s^2

3 0
3 years ago
Read 2 more answers
A permeability test was run on a compacted sample of dirty sandy gravel. The sample was 175 mm long and the diameter of the mold
LUCKY_DIMON [66]

Answer:

(a). The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.

Explanation:

Given that,

Length = 175 mm

Diameter = 175 mm

Time = 90 sec

Volume= 405 cm³

We need to calculate the discharge

Using formula of discharge

Q=\dfrac{V}{t}

Put the value into the formula

Q=\dfrac{405}{90}

Q=4.5\ cm^3/s

(a). We need to calculate the coefficient of permeability

Using formula of coefficient of permeability

Q=kiA

k=\dfrac{Q}{iA}

k=\dfrac{Ql}{Ah}

Where, Q=discharge

l = length

A = cross section area

h=constant head causing flow

Put the value into the formula

k=\dfrac{4.5\times175\times10^{-1}}{\dfrac{\pi(175\times10^{-1})^2}{4}\times38}

k=8.6\times10^{-3}\ cm/s

The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(c). We need to calculate the discharge velocity during the test

Using formula of discharge velocity

v=ki

v=\dfrac{kh}{l}

Put the value into the formula

v=\dfrac{8.6\times10^{-3}\times38}{17.5}

v=0.0187\ cm/s

The discharge velocity during the test is 0.0187 cm/s.

(b). We need to calculate the volume of solid in the ample

Using formula of volume

V_{s}=\dfrac{M_{s}}{V_{s}}

Put the value into the formula

V_{s}=\dfrac{4950\times10^{-3}}{2710}

V_{s}=1826.56\ cm^3

We need to calculate the volume of the soil specimen

Using formula of volume

V=A\times L

Put the value into the formula

V=\dfrac{\pi(17.5)^2}{4}\times17.5

V=4209.24\ cm^3

We need to calculate the volume of the voids

V_{v}=V-V_{s}

Put the value into the formula

V_{v}=4209.24-1826.56

V_{v}=2382.68\ cm^3

We need to calculate the seepage velocity

Using formula of velocity

Av=A_{v}v_{s}

v_{s}=\dfrac{Av}{A_{v}}

v_{s}=\dfrac{V}{V_{v}}\times v

Put the value into the formula

v_{s}=\dfrac{4209.24}{2382.68}\times0.0187

v_{s}=0.0330\ cm/s

The seepage velocity is 0.0330 cm/s.

Hence, (a). The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.

8 0
4 years ago
It is easier to see clothes with pointed needle than a blunt one​
topjm [15]

Answer:

Explanation:

It is easier to see clothes with pointed needle than a blunt one because pressure exerted is more in a pointed needle as it occupies less space compared to blunt needle, A blunt has more surface area so the pressure exerted will less as compared to a pointed needle.

IF YOU FOUND MY ANSWER USEFUL THEN PLEASE MARK ME BRAINLIEST.

7 0
3 years ago
PLEASE ANSWER QUICK!!!
rusak2 [61]

I would say its D.

-hope this helps

3 0
3 years ago
Read 2 more answers
Other questions:
  • Can you use a machine to gain both force and speed at the same time? explain.
    8·1 answer
  • I am doing a physics project where I have to explain the physics behind my instrument I make, I am making an harmonica out of st
    12·1 answer
  • What type of season does Daytona Beach, FL most likely have?
    5·2 answers
  • The intensity of a sound describes
    9·1 answer
  • An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
    14·1 answer
  • Each croquet ball in a set has a mass of 0.53 kg. The green ball, traveling at 14.4 m/s, strikes the blue ball, which is at rest
    6·1 answer
  • Suppose that a large cargo truck needs to cross a bridge. The truck is 30 m long and 3.2 m wide. The cargo exerts a force of 54,
    12·1 answer
  • Consider the stress-strain diagram shown here. Assume all four material samples (A-D) were originally the same size and shape. I
    10·1 answer
  • HELP MEEEEEEEEEEEEEEEEE
    10·1 answer
  • HELPPPPP PLEASEEEEEE
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!