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Hunter-Best [27]
2 years ago
6

Each croquet ball in a set has a mass of 0.53 kg. The green ball, traveling at 14.4 m/s, strikes the blue ball, which is at rest

. Assuming that the balls slide on a frictionless surface and all collisions are head-on, find the final speed of the blue ball in each of the following situations: a) The green ball stops moving after it strikes the blue ball. Answer in units of m/s.b) The green ball continues moving after the collision at 2.4 m/s in the same direction. Answer in units of m/s. c) The green ball continues moving after the collision at 0.9 m/s in the same direction. Answer in units of m/s.
Physics
1 answer:
faust18 [17]2 years ago
8 0

a) 14.4 m/s

The problem can be solved by using the law of conservation of total momentum; in  fact, the total initial momentum must be equal to the final total momentum:

p_i = p_f

So we have:

m_g u_g + m_b u_b = m_g v_g + m_b v_b (1)

where

m_b = m_g = m = 0.53 kg is the mass of each ball

u_g = 14.4 m/s is the initial velocity of the green ball

u_b = 0 is the initial velocity of the blue ball

v_g=0 is the final velocity of the green ball

v_b is the final velocity of the blue ball

Simplifying the mass in the equation and solving for v_b, we find

v_b = u_g = 14.4 m/s

b) 12.0 m/s

This time, the green ball continues moving after the collision at

v_g = 2.4 m/s

So the equation (1) becomes

u_g = v_g + v_b

And solving for v_b we find

v_b = u_g - v_g = 14.4 m/s-2.4 m/s=12.0 m/s

c) 13.5 m/s

This time, the green ball continues moving after the collision at

v_g = 0.9 m/s

So the equation (1) becomes

u_g = v_g + v_b

And solving for v_b we find

v_b = u_g - v_g = 14.4 m/s-0.9 m/s=13.5 m/s

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