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Hunter-Best [27]
2 years ago
6

Each croquet ball in a set has a mass of 0.53 kg. The green ball, traveling at 14.4 m/s, strikes the blue ball, which is at rest

. Assuming that the balls slide on a frictionless surface and all collisions are head-on, find the final speed of the blue ball in each of the following situations: a) The green ball stops moving after it strikes the blue ball. Answer in units of m/s.b) The green ball continues moving after the collision at 2.4 m/s in the same direction. Answer in units of m/s. c) The green ball continues moving after the collision at 0.9 m/s in the same direction. Answer in units of m/s.
Physics
1 answer:
faust18 [17]2 years ago
8 0

a) 14.4 m/s

The problem can be solved by using the law of conservation of total momentum; in  fact, the total initial momentum must be equal to the final total momentum:

p_i = p_f

So we have:

m_g u_g + m_b u_b = m_g v_g + m_b v_b (1)

where

m_b = m_g = m = 0.53 kg is the mass of each ball

u_g = 14.4 m/s is the initial velocity of the green ball

u_b = 0 is the initial velocity of the blue ball

v_g=0 is the final velocity of the green ball

v_b is the final velocity of the blue ball

Simplifying the mass in the equation and solving for v_b, we find

v_b = u_g = 14.4 m/s

b) 12.0 m/s

This time, the green ball continues moving after the collision at

v_g = 2.4 m/s

So the equation (1) becomes

u_g = v_g + v_b

And solving for v_b we find

v_b = u_g - v_g = 14.4 m/s-2.4 m/s=12.0 m/s

c) 13.5 m/s

This time, the green ball continues moving after the collision at

v_g = 0.9 m/s

So the equation (1) becomes

u_g = v_g + v_b

And solving for v_b we find

v_b = u_g - v_g = 14.4 m/s-0.9 m/s=13.5 m/s

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Answer:

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Explanation:

Given:

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For finding the average force,

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   F = \frac{dP}{dt}

Here, final velocity is zero so we write,

 F = \frac{mv}{1}

Where dt = 1 sec

 F = 300 \times 10^{-30} \times 10

F = 3 N

Above value of force is due to one ball, but here given in question there are two ball,

F = 3 \times 2

F = 6 N

Therefore, the average force exerted on the window due to two snowballs is 6 N

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3 years ago
Please help on this one?
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30 or c because 60-30=30

3 0
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The two particles are both moving to the right. Particle 1 catches up with particle 2 and collides with it. The particles stick
Travka [436]

Answer:

c. vf is greator than v2, but less than v1

Explanation:

The principle of conservation of linear momentum states that when two or more bodies act upon one another, their total momentum remains constant.

In a system of colliding bodies the total momentum of the system just before the collision is the same as the total momentum just after the collision.  

Collisions in which the kinetic energy is conserved are called elastic collision.

Collisions in which the kinetic energy is not conserved are called inelastic collisions.  If the two objects stick together after the collision and move with a common velocity, the collision is said to be perfectly inelastic.

<em>The above scenario is a perfectly inelastic collision. The initial velocity of particle 1 was greater than particle 2 before collision. After collision, its velocity will reduce to a final velocity vf as it transfers some of its kinetic energy to particle 2; whereas, the velocity of particle 2 will increase to a final velocity vf as it absorbs some of the kinetic energy of particle 1.</em>

Therefore,

a. vf = v2 is wrong because vf is greater than v2

b. vf is less than v2 is wrong because vf is greater than v2

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d. vf = v1 is wrong because vf is less than v1

4 0
3 years ago
What effect would this have on the momentum?
Mariana [72]
Momentum describes an object in motion and is determined by the product of two variables: mass and velocity. Mass -- the weight of an object -- is usually measured in kilograms or grams for momentum problems. Velocity is the measure of distance traveled over time and is normally reported in meters per second. Examining the possible changes in these two variables identifies the different effects momentum can have on an object in motion.
6 0
3 years ago
A jet plane lands with a velocity of +107 m/s and can accelerate at a maximum rate of -5.18 m/s2 as it comes to rest. From the i
Marrrta [24]

Answer:

20.7 s

Explanation:

The equation to calculate the velocity for a uniform acceleration a, time t and initial velocity v₀:

v = a*t + v₀

Solve for t:

t = (v - v₀)/a

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3 years ago
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