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3 years ago

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Consider the stress-strain diagram shown here. Assume all four material samples (A-D) were originally the same size and shape. I

dentify the material with the highest yield strength:
Stress-strain diagram with 4 materials graphed.

A

B

C

D

1 answer:

salantis [7]3 years ago

5 0

Answer:

B

Explanation:

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The earth’s radius is 6.37 × 10 6 m ; it rotates once every 24 hours. What is the earth’s angular speed? Viewed from a point abo

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Answer:

a) the angular speed of the Earth's rotation is <em>7.272 × 10⁻⁵ rad/s.</em>

<em></em>

b) Viewed from the North Pole, Earth's angular speed rotates in an anticlockwise direction. Therefore, the <em>angular velocity is positive.</em>

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c) Earth's speed at a point on the equator is <em>463.23 m/s.</em>

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d) the speed of a point on the earth’s surface halfway between the equator and the pole is <em>231.61 m/s.</em>

Explanation:

a) The angular speed of the Earth's rotation is:

ω = 2π / T

where

T is the period

ω = 2π / (24 hr × (3600 s / 1 hr))

<em>ω = 7.272 × 10⁻⁵ rad/s</em>

b) Viewed from the North Pole, Earth's angular speed rotates in an anticlockwise direction. Therefore, the <em>angular velocity is positive.</em>

c) Earth's speed at a point on the equator is:

v = r × ω

v = (6.37 × 10⁶ m) × (7.272 × 10⁻⁵ rad/s)

<em>v = 463.23 m/s</em>

d) The radius of the circle in which the point moves is half of Earth's radius. Therefore,

r = 1/2(6.37 × 10⁶ m)

r = 3.19 × 10⁶ m

Therefore, the speed of a point on the earth’s surface halfway between the equator and the pole is:

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If Maria lifts a mass of 10kg into a table of 1.25m high. How much gpe has the mass gained

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Answer:

gravitational potential energy of 10 kg mass is 122.625 J

Explanation:

Gravitational Potential energy gain is given as

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here we know that

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h = 1.25 m

now from above formula we have

$U = (10)(1.25)(9.81)$

$U = 122.625 J$

So gravitational potential energy of 10 kg mass is 122.625 J

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Answer:

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