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Molodets [167]
3 years ago
14

At 6:00 A.M., the temperature was 62°F. The temperature then increased about 3° every hour. What is the BEST

Mathematics
2 answers:
Anton [14]3 years ago
7 0

Answer:80

Step-by-step explanation:

Anna35 [415]3 years ago
6 0

Answer:

i dont know sup man give me your girl

Step-by-step explanation:

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I NEED SERIOUS HELP ON THIS HOLE HW ASSIGNMENT OR I GET AN F .
Tcecarenko [31]

Answer:

6, 9, 18

Step-by-step explanation:

3 0
2 years ago
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After extensive measurements of the time necessary to complete the first homework assignment, a teacher determines that there is
MaRussiya [10]

Answer: -1.55

Step-by-step explanation:

Given : Mean : \mu=100

Standard deviation : \sigma=20

Sample size : n=60

Sample mean : \overline{x}=96

The test statistic for the population mean is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{96-100}{\dfrac{20}{\sqrt{60}}}=-1.54919333848\approx-1.55

Hence, the value of z statistic = -1.55

4 0
3 years ago
Steps for showing percent of 2028÷30%
4vir4ik [10]
2028/x=100/30
<span>(2028/x)*x=(100/30)*x       </span>we multiply both sides of the equation by x
<span>2028=3.3333333333333*x       </span>we divide both sides of the equation by (3.3333333333333) to get x
<span>2028/3.3333333333333=x </span>
<span>608.4=x </span>
<span>x=608.4
so there for its 608.4 hope this helps.</span>
6 0
3 years ago
Read 2 more answers
Need help finding the answers
Alex777 [14]
8=384        9=248   hope this helped 
7 0
3 years ago
On the first visit to the veterinarian's office, Cora's kitten weighted 550 grams.
tamaranim1 [39]

old (first visit): 550 grams

second visit: gained 350 grams

third visit: gained 300 grams

new: cora's kitten is now 1200 grams.

-> now, we must find the percent increase between 550 and 1200.

to find percent increase, we use this equation

new - old / old x 100

-> (1200 - 550 / 550) x 100

   (650 / 550) x 100

   = 1.18 x 100

 <u>percent increase: 118% </u>

<u></u>

✧ hope this helped!

- aure

8 0
3 years ago
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