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3 years ago

Evaluate square root of 16 minus x end root when x = 8.

Mathematics

1 answer:

My name is Ann [436]3 years ago

7 0

$\sqrt{16-x}$
x=8
16-8=8
$\sqrt{8}$

Use a calculator to find the square root of 8.

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The law of cosines is used to find the measure of Z.

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Answer:

C. $Z=51^{\circ}$

Step-by-step explanation:

We have been given a triangle. We are asked to find the measure of angle Z using Law of cosines.

Law of cosines: $c^2=a^2+b^2-2ab\cdot \text{cos}(C)$ , where, a, b and c are sides opposite to angles A, B and C respectively.

Upon substituting our given values in law of cosines, we will get:

$16^2=19^2+18^2-2(19)(18)\cdot \text{cos}(Z)$

$256=361+324-684\cdot \text{cos}(Z)$

$256=685-684\cdot \text{cos}(Z)$

$256-685=685-685-684\cdot \text{cos}(Z)$

$-429=-684\cdot \text{cos}(Z)$

$\frac{-429}{-684}=\frac{-684\cdot \text{cos}(Z)}{-684}$

$0.627192982456=\text{cos}(Z)$

$\text{cos}(Z)=0.627192982456$

Now, we will use inverse cosine or arc-cos to solve for angle Z as:

$Z=\text{cos}^{-1}(0.627192982456)$

$Z=51.1566718^{\circ}$

$Z\approx 51^{\circ}$

Therefore, the measure of angle Z is approximately 51 degrees.

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