Answer:
The maximum height of ball 2 is 4 times that of ball 1
Explanation:
We can find the maximum height of each ball by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
is the acceleration of gravity (we take upward as positive direction)
s is the displacement
At the maximum height, s = h and v = 0 (the final velocity is zero), so re-arranging the equation:
The first ball is thrown with initial velocity , so it reaches a maximum height of
(the quantity will be positive, since g is negative)
The second ball is thrown with initial velocity
so it will reach a maximum height of
So, its maximum height will be 4 times the maximum height reached by ball 1.