1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VashaNatasha [74]
3 years ago
8

Help ;-;

Physics
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

all qn 1,2,3 have same answer ,. Yes,. hope it helps

You might be interested in
Science questions!! Please help!!
kondor19780726 [428]

Answer:

1. b

2. c

3. b

4. a

5. a

6. c

7. c

8. d

7 0
3 years ago
A 15x10^-6c charge is placed at the origin and a 9x10^-6C charge is placed on the x-axis at x=1.00m. where, on the x-axis is the
Harlamova29_29 [7]

The Electric field is zero at a distance 2.492 cm from the origin.

Let A be point where the charge 15\times10^-6 C is placed which is the origin.

Let B be the point where the charge 9\times 10^-6 C is placed. Given that B is at a distance 1 cm from the origin.

Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.

i.e., at distance 'x' from B.

Using Coulomb's law, \frac{kQ_A^2}{d_A^2} = \frac{kQ_B^2}{d_B^2},

Q_A = 15\times 10^-6 C

Q_B=9\times10^-6C

d_A = 1+x cm

d_B=x cm

k is the Coulomb's law constant.

On substituting the values into the above equation, we get,

\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}

Taking square roots on both sides and simplifying and solving for x, we get,

1.67x = 1+x

Therefore, x = 1.492 cm

Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.

Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926

#SPJ4

3 0
1 year ago
Please help please help
Inessa [10]

Answer: p= m/v so 90kg/.075m^3 = 1,200

2a. .35 m 1.1 m and .015 m

2b. 35 cm x 110 cm x 1.5 cm = 5,775 cm^3 = 57.75 m^3

mass= pv

2700•57.75= 155,925 kg

mass= 155,925 kg

volume= 57.75 m^3

Explanation: physics

6 0
3 years ago
Two balls, each with a mass of 0.890 kg, exert a gravitational force of 8.06 × 10−11 n on each other. how far apart are the ball
Bond [772]
This problem involves Newton's universal law of gravitation and the equation to follow would be.

F = GM₁M₂/r²  

Given: M₁ = 0.890 Kg;  M₂ = 0.890 Kg;  F = 8.06 x 10⁻¹¹ N; G = 6.673 X 10⁻¹¹ N m²/Kg²

Solving for distance r = ?

r = √GM₁M₂/F

r = √(6.673 x 10⁻¹¹ N m₂/Kg²)(0.890 Kg)(0.890 Kg)/ 8.06 x 10⁻¹¹ N

r = 0.81 m 
6 0
3 years ago
If the horizontal component of a vector is 6 m/s and the vertical component is also 6 m/s, what is the resultant value of the ve
BlackZzzverrR [31]
Resultant force= (2*6^2)^(1/2)
=8.5m/s
answer is B.
6 0
3 years ago
Other questions:
  • What is the acceleration of the object?
    10·1 answer
  • How does speed affect momentum
    14·2 answers
  • In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is
    15·2 answers
  • A series RL circuit contains two resistors and two inductors. The resistors are 33 Ω and 47 Ω. The inductors have inductive reac
    11·1 answer
  • QUESTION 10
    11·1 answer
  • An iron nail floats in mercury and sinks in water. explain why?​
    7·1 answer
  • Thermodynamic Processes: An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will
    12·1 answer
  • 3 write the three laws given by kepler.How did they help Newton to arrive at the inverse square law of gravity?​
    13·1 answer
  • 5. The force of gravity acting on the object is object’s ______________.
    8·1 answer
  • Which is the best example of the use of imagery in a sentence?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!