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daser333 [38]
3 years ago
5

A pmdc has a stall torque of 10 and maximum mechanical power of 200. What is the maximum angular velocity?

Physics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

The maximum angular velocity is 20 rad/s

Explanation:

Given;

torque, τ = 10 N

maximum mechanical power, P = 200 J/s

The output power of the pmdc is given as;

P = τω

where;

P is the maximum mechanical power

ω is the maximum angular velocity

ω = P / τ

ω = (200) / (10)

ω = 20 rad/s

Therefore, the maximum angular velocity is 20 rad/s

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A solution is oversaturated with solute. Which could be done to decrease the oversaturation?
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Answer : The correct option is, (A) dilute the solution

Explanation :

Saturated solution : It is a solution in which the maximum concentration of the solute dissolved in the solvent. The additional amount of the solute will not be dissolved in saturated solution.

Unsaturated solution : It is a solution in which the minimum concentration of the solute dissolved in the solvent. The additional amount of the solute will dissolved in unsaturated solution.

As per given question, when the solution is over-saturated with the solute then to decrease the over-saturation we will dilute the solution. That means more amount of solvent will be added to the over-saturated solution.

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Which factors can affect the amount of friction acting on an object on a solid surface
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The ratio of carbon-14 to nitrogen in an artifact is 1:1 . Given that the half-life of carbon-14 is 5730 years, how old is the a
Troyanec [42]

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Lamda= ln 2÷ half life,t(1/2)

Lamda= ln2= 0.693/5730 years

Lamda=1.21 × 10^-4

Using the formula below;

Age,t= 1/lamda× (ln {1+ Dt/Pt})------------------------------------------------------------------------------------(1)

Slotting our values into equation (1) above.

Age,t= 1/lamda(ln[1+1/1])

Age,t= 1/1.2×10^-4(ln 1+1)

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Age,t= ln 2/ 1.21×10^-4

Age, t= 5,728.5 years.

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A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 130 m above the
QveST [7]

Answer:

t =\sqrt{\frac{2*(-100m)}{-9.8 m/s^2}}= 4.518 s

And now we can find the final distance on the x axis using the formula:

D = V_x t

The velocity on x not changes and is the same plane spped V_x = 150 m/s, if we replace we got:

X= 150 m/s * 4.518 s= 677.63 m

Explanation:

For this case we have a illustration for the problem in the figure attached.

We need to find how far short of the target should be the plane, we have the following info given:

v_{ix}= 150 m/s

v_{iy}=0 m/s

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y_i =0m

x_i = 0m

How far short of the target should it drop the package?

First we can find the total time in order to reach the groung using the following kinematic formula:

y_f = y_i + v_{iy} +\frac{1}{2}gt^2

And replacing we have:

-100 m = 0 +0 -\frac{1}{2} (9.8 m/s^2) t^2

And solving for t we got:

t =\sqrt{\frac{2*(-100m)}{-9.8 m/s^2}}= 4.518 s

And now we can find the final distance on the x axis using the formula:

D = V_x t

The velocity on x not changes and is the same plane spped V_x = 150 m/s, if we replace we got:

X= 150 m/s * 4.518 s= 677.63 m

8 0
3 years ago
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