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2 years ago

Write the standard form of the quadratic equation modeled by the points shown in the table below.

Mathematics

2 answers:

rjkz [21]2 years ago

5 0

Answer:

y = 2x² - 5x + 7

Step-by-step explanation:

General form of a quadratic is:

y = Ax² + Bx + C

Using the given points, construct equations and solve for A,B and C.

When x = 0, y = 7

7 = A(0)² + B(0) + C

C = 7

y = Ax² + Bx + 7

When x = -1, y = 14

14 = A(-1)² + B(-1) + 7

A - B = 7

A = 7 + B

When x = 1, y = 4

4 = A(1)² + B(1) + 7

A + B = -3

(7 + B) + B = -3

2B = -10

B = -5

A = 7 + (-5)

A = 2

y = 2x² - 5x + 7

sattari [20]2 years ago

4 0

General form of a quadratic is:

y = Ax² + Bx + C

Using the given points, construct equations and solve for A,B and C.

When x = 0, y = 7

7 = A(0)² + B(0) + C

C = 7

y = Ax² + Bx + 7

When x = -1, y = 14

14 = A(-1)² + B(-1) + 7

A - B = 7

A = 7 + B

When x = 1, y = 4

4 = A(1)² + B(1) + 7

A + B = -3

(7 + B) + B = -3

2B = -10

B = -5

A = 7 + (-5)

A = 2

y = 2x² - 5x + 7

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The area of a triangle is 20 cm², and the

grandymaker [24]

Answer:

Heavenly, we need the forumula for the area of a triangle, do you know it?

Step-by-step explanation:

Area of a triangle is (1/2 ) * B*H

where B = base

H = height

then

A = 1/2* B * H

A is given to be 20

B = b

H = b+4

plug all those into the formula,

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use your algebra skillz :P

20 = 1/2 *( $b^{2}$ + 4b)

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rewrite the above so it's in x format

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use the quadratic formula to find x , and for our problem, remember that x represents the base, or b, but don't mix it up with the b in the quadatic fomula, with the b of the triangle, which is the base, they are differnt "b"s :P

X = (b± $\sqrt{b^{2}-4*a*c }$ ) / 2*a