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Novosadov [1.4K]
3 years ago
7

There are 2 sets of balls numbered l through 19 placed in a bowl. If 2 balls are randomly chosen without replacement, find the p

robability that the balls have the same number. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth. ​
Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

0.027027

Step-by-step explanation:

2 x 19= 38

38C2=703

19/703=0.027027

You

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P varies jointly with t and inversely with s. If p = 4 when t = 3 and s = 6, find p when t = -6 and s = 2.
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Step-by-step explanation:

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3 years ago
How many rectangle 5cm multiply 2cm <br> Can fits in a square that has one side 10cm long
Sliva [168]

Answer:

<u>10</u> rectangles can fit in the square that has one side 10 cm long.

Step-by-step explanation:

Given:

Rectangle 5 cm multiply 2 cm .

Square that has one side 10cm long.

Now, to find the number of rectangle that can fits in the square.

So, for getting the number of rectangle we need to get the area first:

Area of rectangle as given 5 cm multiply 2 cm :

5\ cm\times 2\ cm=10\ cm^2

Then the area of square as given side is 10 cm:

Area of square = (side)²

Area\ of\ square=10^2

Area\ of\ square=100\ cm^2

Now, for getting the number of rectangle we divide the area of square by area of rectangle:

Number of rectangle = Area of square ÷ Area of rectangle

Number\ of\ rectangle=100\ cm^2\div 10\ cm^2

Number\ of\ rectangle=10.

Therefore, 10 rectangles can fit in the square that has one side 10 cm long.

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3 years ago
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timama [110]

Answer:

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Having trouble,Whats 1/3 (-2/4)
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Answer:

-1/6

Step-by-step explanation:

im assuming you meant multiply them? if so then

1         -2            -2           -1

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or

1/3=4/12 and -2/4=-6/12

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