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Wewaii [24]
3 years ago
8

What is the solution to the linear equation 2.8y+6+0.02y=5y-14

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0
Group all the 'y' terms on the left and all the other terms on the right:

<span>2.8y+6+0.02y=5y-14 => y(2.8+0.02-5)=-14-6

Now add up 2.8, 0.02 and -5; then combine -14 and -6.  Can you now solve for y?

</span>
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MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
Find the output for the following function machine when x = 5
seropon [69]

Answer:

24

Step-by-step explanation:

-2×5=-10

-10+34= 24

8 0
3 years ago
1• (a + 3) = a + 3<br> What is the property
Artist 52 [7]

Answer:

the commutative property because you’re not changing the way its form style, but of more like their former

6 0
3 years ago
Y=2x +1 x=3. how do I find the Y in each equation
fiasKO [112]
Since we already have X, I'm guessing all the question asks you to do is plug it in and solve it to get a Y= equation

If I'm right, then the process is

Y=2(3)+1 (putting 3 in place of x)

Y=6+1

Y=7

Which makes 7 your answer
8 0
3 years ago
Read 2 more answers
An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $1790 and his st
stiv31 [10]

Answer:

20.7%

Step-by-step explanation:

Amount of stock increased in Company A = 20% of 1790

           = 0.20 * 1790 = $ 358

Investor's stock in company A this year = 1790 + 358 = $ 2148

Amount of stock increased in Company B = 22% of 1000

           = 0.22 * 1000= $ 220

Investor's stock in company B this year = 1000 + 220 = $ 1220

Total amount in investor's stock account  = 2148 + 1220 = $ 3368

Increased amount = 3368 - 2790 = $ 578

Increase percentage = \frac{578}{2790}*100 = 20.71

                                   = 20.7%

7 0
3 years ago
Read 2 more answers
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