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Wewaii [24]
3 years ago
8

What is the solution to the linear equation 2.8y+6+0.02y=5y-14

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0
Group all the 'y' terms on the left and all the other terms on the right:

<span>2.8y+6+0.02y=5y-14 => y(2.8+0.02-5)=-14-6

Now add up 2.8, 0.02 and -5; then combine -14 and -6.  Can you now solve for y?

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Pls help have to turn in soon
hjlf

Answer:

The one you already have selected along with

428

Step-by-step explanation:

anything to the 0 power is itself

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2 years ago
Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x
charle [14.2K]

The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

Step-by-step explanation:

The given is,

             a = 5

             b = x - 1

             c = x

Step:1

      Pythagorean theorem is,

              a^{2} + b^{2} = c^{2}................................(1)

      (  It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

      From the given values the equation (1) becomes,

                       5^{2} + (x-1) ^{2} = x^{2}

                             ( (a-b)^{2} = a^{2}  + b^{2} -2ab )

               25 + ( x^{2} + 1 - 2x ) = x^{2}

                           25 + 1 -2x = 0               ( ∵ Eliminate x^{2} in both sides)

                                     26 = 2x

                                       x = 13

Step:2

        From the values of x,

                   a = 5

                    b = ( 13 - 1 ) = 12

                   c = 13

Result:

            The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

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3 years ago
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Answer:

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Step-by-step explanation:

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Ae is an angle bisector of
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