Answer:
16
Step-by-step explanation:
count them all together and the right triangles add an additional number of triangles so there are 16 altogether
plus I don't know how you would get the other answers because that is the only one that makes sense if you are including overlapping and stuff because there are technically only 3 triangles actually shown here without taking out any other lines or ignoring them but for your purposes there are 16
143 players per 11 teams.
If you would like to know how many players are in each group, you can calculate this using the following step:
143 players / 11 teams = 143 / 11 = 13 players per group
Result: There are 13 players in each group.
The event "Atleast once" is the complement of event "None".
So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.
At Morning, the probability that Marvin does not teleport = 2/3
Likewise, the probability tha Marvin does not teleport during evening is also 2/3.
Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.
So, the probability that Marvin does not teleport during the day = 
Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.
Probability that Marvin teleports atleast once during the day = 
Answer:
81.5
Step-by-step explanation:
Answer:
4/675
Step-by-step explanation:
There can be 90 two-digit numbers ranging from 10 to 99. There will be
90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses these possibilities is thus 48/8100 = 4/675.