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Airida [17]
3 years ago
11

The precipitator uses a high voltage DC power supply to provide a set of wires with a positive charge and a set of plates with a

_____ charge.
Physics
1 answer:
vazorg [7]3 years ago
6 0

Answer : Negative charge

Explanation :

An electrostatic precipitator is a device that is used to remove dust particles and smoke from a gas.

It consists of a stack of plates. The gas flows via the spaces between the wires. Then it passes to the stack of plates.

A high voltage power supply is applied between wires and the plates. A positive charge is applied to the set of wires and a negative charge is applied to the plates.

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17. How long does it take a giraffe running at a speed of 33 m/s to run 200 meters !
scZoUnD [109]

Answer:

6600sec

Explanation:

T=sv

T=200m*33m/s

T=6600sec

5 0
2 years ago
what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit​
wel

Answer:

-11.11 degree Celsius

Explanation:

The change was 44 degree fanhereit

To 56 degree fanhereit

Therefore the temperature range can be calculated as follows

56-44

= 12 degree fanhereit to Celsius

= 12-32×5/9

= -20×5/9

= 100/9

= -11.11 degree Celsius

5 0
2 years ago
Which of the following statements is the best definition of climate?
noname [10]
Climate is a particular place's distance from the equator
4 0
3 years ago
If force and displacement are in opposite directions, will work be positive or negative?
eimsori [14]
It would be negative regardless of what you define as a positive direction.
8 0
3 years ago
A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At
GuDViN [60]

Answer:

E/4

Explanation:

The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

Where;

E is the electric field

σ is the surface charge density

ε₀ is the electric constant.

Formula to calculate σ is;

σ = Q/A

Where;

Q is the total charge of the sheet

A is the sheet's area.

We are told the elastic sheet is a square with a side length as d, thus ;

A = d²

So;

σ = Q/d²

Putting Q/d² for σ in the electric field equation to obtain;

E = Q/(2ε₀d²)

Now, we can see that E is inversely proportional to the square of d i.e.

E ∝ 1/d²

The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.

From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;

E_new = E/4

3 0
3 years ago
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