A=(v2-v1)/t
v2=0,6m/s
v1=2,4m/s
t=4s
a=(0,6-2,4)/4=-1,8/4=-0,45 m/s^2
The formula written in the 3rd line above the picture is WRONG. Don't use it. Use the formula the way it's printed in the picture.
V = d / t
That means Speed = (distance) / (time)
The question tells us that v = 330 m/s
So you write 330 m/s in the equation in place of 'v', like this:
330 m/s = (distance) / (time)
The question also tells us that the time is 0.4 second
So you write 0.4 sec in place of 'time', like this:
330 m/s = (distance) / (0.4 second)
Finally, you take this, and multiply each side of the equation by (0.4 sec). Then it'll say
distance = (330 m/s) x (0.4 second)
As soon as you do that one single multiplication there with your pencil or your calculator, you'll have the distance.
This is either the 2nd or 3rd time you've posted this same exact question since last weekend. It can be solved THIS time exactly like the answers that were posted those other times.
The DOT in the picture is marked for the wrong choice. Use the formula that's printed in the picture, not copied above it.
A car A house A phone they all can be renewable
N₂ / N₁ = 13.3
A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is
ΔV₂ = N₂ /N₁ ΔV₁
where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.
They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.
ΔV₂ /ΔV₁ = N₂ / N₁
N₂ / N₁ = 120/9
N₂ / N₁ = 13.3
Learn more about voltage here brainly.com/question/16774947
#SPJ4.
A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?
