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3 years ago

8th grade will give brainliest there are no answers to this question

2 answers:

8 0

N order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. Microwaves (like the ones used in microwave ovens) are a subsection of the radio wave segment of the EM spectrum.

rodikova [14]3 years ago

7 0

Answer:

The electromagnetic spectrum is a continuum of all electromagnetic waves arranged according to frequency and wavelength. The sun, the earth and other objects radiate electromagnetic energy of different wavelengths. ...The spectrum of a wave is divided into multiple parts according to wavelength.

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The atom in the diagram has a neutral charge how many protons does it have

Olegator [25]

Explanation:

This should be of help:

An atom is made up of three subatomic particles:

Protons are the positively charged particles.
Electrons are the negatively charged particles.
Neutrons do not carry any charges.

A neutral atom is an atom that has not lost or gained any amount of electrons.

In a neutral atom;

the number of protons and electrons are the same

Usually atoms are designated this way:

ᵃₙX

where X is the symbol of the atom

a is the mass number of the atom

n is the atomic number of the atom

The mass number = number of protons + number of neutrons

Atomic number = number of protons

Note; atomic number is the same as the number protons and the number of electrons in a neutral atom.

Use this guide to solve the problem

Learn more:

Atomic number brainly.com/question/5425825

#learnwithBrainly

8 0

3 years ago

How many laws does newton have?

liq [111]

Newton has 3 Laws specifically The Three Laws of Motion

3 0

3 years ago

1. A child standing on a bus remains still when the bus is at rest. When the bus moves

dedylja [7]

Answer:

Explanation:

8 0

2 years ago

Read 2 more answers

roblem 10: In an adiabatic process oxygen gas in a container is compressed along a path that can be described by the following p

miskamm [114]

Answer:

W= -2.5 (p₁*0.0012) joules

Explanation:

Given that p₀= initial pressure, p₁=final pressure, Vi= initial volume=0 and Vf=final volume= 6/5 liters where p₁=p₀ then

In adiabatic compression, work done by mixture during compression is

W= $\int\limits^f_i {p} \, dV$ where f= final volume and i =initial volume, p=pressure

p can be written as p=K/V^γ where K=p₀Vi^γ =p₁Vf^γ

W= $\int\limits^f_i {K/V^} \, dV$

W= K/1-γ ( 1/Vf^γ-1 - 1/Vi^γ-1)

W=1/1-γ (p₁Vf-p₀Vi)

W= 1/1-1.40 (p₁*6/5 -p₀*0)

W= -2.5 (p₁*6/5*0.001) changing liters to m³

W= -2.5 (p₁*0.0012) joules

3 0

2 years ago

A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m

Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force $F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k$

Mass of object = 2.00 kg

Initial position $d=(2.75)i-(2.00)j+(5.00)k$

Final position $d=-(5.00)i+(4.50)j+(7.00)k$

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

$W=F\cdot d$

$W=F\cdot(d_{f}-d_{i})$

Put the value into the formula

$W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)$

$W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)$

$W=2.75\times-7.75+7.50\times6.50+6.75\times2.00$

$W=40.93\ J$

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0

2 years ago