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elixir [45]
3 years ago
8

When astronomers observe the spectra of distant galaxies,they notice that the hydrogen emission lines are shifted noticeably tow

ard the red end of the visual spectrum,a phenomenon called red shift. Red is lowest frequency of visible light. What does red shift indicate about the movement of the distant galaxies?
Physics
1 answer:
34kurt3 years ago
5 0
The amount of redshift increases in relation with the distance, meaning, the larger the redshift, the more distant the galaxy.  The Hubble diagram which was created by Edwin Hubble in 1929 shows that the more redshifted a galaxy is the further away it is. The galaxies are moving away from Earth because the fabric of space itself is expanding.  <span>Subtle changes in the color of starlight let </span>astronomers<span> find planets,  </span>measure<span> the speeds of </span>galaxies<span>, and track the expansion of the universe. </span>
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What happens to water when it changes to ice?
mamaluj [8]

When water changes to ice, its density decreases and its volume increases.

7 0
3 years ago
When a warm air mass is trapped between two cooler air masses, it is called a/an
Semenov [28]
The answer is C. An occluded front.
8 0
3 years ago
I need to know the right answer to that question
ad-work [718]
The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)

Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation

v = vo + at

When you plug in the values you get

v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
8 0
3 years ago
How does the orbital speed of an asteroid in a circular solar orbit with a radius of 4.0 AU compare to a circular solar orbit wi
Murrr4er [49]

Answer:

The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU

Explanation:

am = mvr= angular momentum

am4= 4mvt

am1= mvp1

Vt=1/4vp

Vp=4vt

am1= 4mvt

am1=am4

The circular solar orbital speed at 4.0AU is 1/4 (one fourth) that at 1.0AU

6 0
3 years ago
You are given a parallel plate capacitor that has plates of area 29 cm2 which are separated by 0.0100 mm of nylon (dielectric co
GalinKa [24]

Answer:

20.60 kV

Explanation:

Capacitance of parallel plates without dielectric between them is:

C=\frac{\varepsilon_{0}A}{d}

with d the distance between the plates, A the area of the plates and ε₀ the constant 8.85419\times10^{-12}\frac{C^{2}}{Nm^{2}}, so :

C_0=\frac{(8.85419\times10^{-12})(0.0029)}{0.0100\times10^{-3}}=2.57\times10^{-9} F

But the dielectric constant is defined as:

k=\frac{C}{C_{0}}

With C the effective capacitance (with the dielectric) and Co the original capacitance (without the dielectric). So, the new capacitance is:

C=kC_0

But capacitance is related with voltage by:

C=\frac{Q}{V}

with Q the charge and V the voltage, using the new capacitance and solving for V:

kC_0=\frac{Q}{V}

V=\frac{Q}{kC_0}=\frac{0.18\times10{-3}}{(3.4)(2.57\times10^{-9})}=20599.68V=20.60 kV

4 0
3 years ago
Read 2 more answers
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