Compute the concentration of HCl for all three trials using the formula molarity = mol / L. Trial 1 (20.61 mL HCl): M Trial 2 (2
0.06 mL HCl): M Trial 3 (19.67 mL HCl): M
2 answers:
Answer:
Trial 1 (20.61 mL HCl):
⇒ 0.121 M
Trial 2 (20.06 mL HCl):
⇒ 0.125 M
Trial 3 (19.67 mL HCl):
⇒ 0.122 M
the answer for the next question, Compute the average concentration (molarity) of HCl for all three trials, is 0.123 M.
Explanation:
Answer:
Trial 1 (20.61 mL HCl):
⇒ 0.121 M
Trial 2 (20.06 mL HCl):
⇒ 0.125 M
Trial 3 (19.67 mL HCl):
⇒ 0.122 M
0.123 M.
Explanation:
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