All categories

3 years ago

At every depth, soil composition remains the same. O True O False

Chemistry

2 answers:

pickupchik [31]3 years ago

7 0

Answer:

false

Explanation:

Hope the answer was usefull for us

aniked [119]3 years ago

7 0

Answer:

false. there is the surface soil, which has a lot of partly decayed stuff, topsoil, which has minerals and organic material, subsoil, which is made from sand, silt, and clay that hasn't been broken down, and parent material, which is the place where not much living things live in, except for gigantic tree roots. then there is the bedrock, which is; you guessed it:rock entirely.

Explanation:

You might be interested in

What is conjugate solution

mars1129 [50]

Answer:

Explanation: A mixture of two partially miscible liquids

5 0

3 years ago

How many moles of carbon dioxide gas can be produced when 7.94 moles of benzene (C6H6) react with excess oxygen? Be sure to show

Sliva [168]

The balanced equation is

2 C6H6 +15 O2 = 12 CO2 + 6 H2O 

the ratio between C6H6 and CO2 is 2 : 12 

moles CO2 produced = 7.94 x 12 / 2 =47.6

6 0

3 years ago

One mole of carbon, sulfur, and aluminum, respectively. Which jar contains the most atoms?

forsale [732]

Answer:

sulphur cuz its weight is 32.065g

Explanation:

this is correct

plz mark me brainliest

7 0

3 years ago

Read 2 more answers

35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? A

dusya [7]

Given:

35.0 mL of acid with an unknown concentration

24.6 mL of 0.432 M base

Required:

Concentration of the acid

Solution:

M1V1 = M2V2

M1 (35.0 mL of acid) = (0.432 M base) (24.6 mL of base)

V1 = (0.432 M base) (24.6 mL of base) / (35.0 mL of acid)

M1 = 0.304 M of acid

5 0

3 years ago

The density of liquid mercury is 13.6 g/mL. What is its density in units of ? (2.54 cm = 1 in., 2.205 lb = 1 kg)

nalin [4]

Correct question

The density of liquid mercury is 13.6 g/mL. What is its density in units of lb/in3? (2.5 cm = 1 in., 2.205 lbs= 1 kg., 1000 g =1 kg, 1 mL = 1 cm³)

Answer:

$\rho0.4916\ lb/in^3$

Explanation:

Given that;-

The density = 13.6 g/mL

Also, 1 kg = 2.205 lb

1 kg = 1000 g

So, 1000 g = 2.205 lb

1 g = 0.002205 lb

Also,

1 in = 2.54 cm

1 in³ = 16.39 cm³

1 cm³ = 1 mL

So, 1 in³ = 16.39 mL

1 mL = 0.061 in³

The expression for the calculation of density is shown below as:-

$\rho=\frac{m}{V}$

Thus,

$\rho=\frac{13.6\ g}{1\ mL}=\frac{13.6\times 0.002205\ lb}{0.061\ in^3}=0.4916\ lb/in^3$

7 0

3 years ago