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3 years ago

At every depth, soil composition remains the same. O True O False

Chemistry

2 answers:

pickupchik [31]3 years ago

7 0

Answer:

false

Explanation:

Hope the answer was usefull for us

aniked [119]3 years ago

7 0

Answer:

false. there is the surface soil, which has a lot of partly decayed stuff, topsoil, which has minerals and organic material, subsoil, which is made from sand, silt, and clay that hasn't been broken down, and parent material, which is the place where not much living things live in, except for gigantic tree roots. then there is the bedrock, which is; you guessed it:rock entirely.

Explanation:

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What keeps gravitational force beteen two objects unchanged

hichkok12 [17]

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2 years ago

Which elements have the quantum numbers (4,3,-2,+1/2) and (5,2,-1,-1/2)

nikklg [1K]

The elements are samarium (Sm) and silver (Ag).

Quantum numbers (4,3,-2,+½)

n = 4: Principal quantum number = 4.

l = 3: Element has 4f electrons

It is conventional to list quantum numbers in decreasing order.

Hund’s rule states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.

We get the following table:

Element n l mₗ mₛ

La 4 3 3 +½

Ce 4 3 2 +½

Pr 4 3 1 +½

Nd 4 3 0 +½

Pm 4 3 -1 +½

Sm 4 3 -2 +½

The element is samarium, Sm.

Quantum numbers (5,2,-1,-½)

n = 5: Principal quantum number = 5.

l = 2: Element has 5d electrons

We get the following table:

Element n l mₗ mₛ

Y 5 2 2 +½

Zr 5 2 1 +½

Nb 5 2 0 +½

Mo 5 2 -1 +½

Tc 5 2 -2 +½

Ru 5 2 2 -½

Rh 5 2 1 -½

Pd 5 2 0 -½

Ag 5 2 -1 -½

The element is silver, Ag.

Note: These assignments assume that there are no exceptions in the Periodic Table.

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3 years ago

A 125g sample of a mixture of salt and sand contains 12% salt.

natka813 [3]

12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
12 * 125 / 100 = 15 g of salt is present in 125 g mixture.
b. The amount of sand can be calculated similarly, 88 %
of 125 g is 88 * 125 / 100 = 110 g of sand is present in
125 g mixture.

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2 years ago

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Katena32 [7]

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3 years ago

How many bacteria can fit into an animal cell

melisa1 [442]

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3 years ago