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natulia [17]
3 years ago
14

Find the value of -8 + 9 · 2 ÷ -3. -2/3 -2 -11 -14

Mathematics
1 answer:
Viktor [21]3 years ago
6 0

Answer:

the answer is D.14

Step-by-step explanation:

You do 9 ×2=18

18÷-3=-6

-8+-6=14

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4 0
2 years ago
Will give brainlest plz help!!!Which relation is a function?
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The correct answer is the graph in the top right corner because it is a constant function. The bottom left graph is also considered a function but is an absolute function. So both are technically correct.

5 0
3 years ago
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12. Car insurance that pays for your injuries when you're in an accident in your car is
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C. Medical expenses

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7 0
3 years ago
A student earned grades of 84, 78, 84, and 72 out of 100 on her four regular tests. She scored 78% on the final exam and 86% on
adelina 88 [10]

If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.

<h3>What is mean?</h3>

The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.

On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.

You may compute the weighted mean as follows:

\rm W_m= 0.4 \times ( \frac{84+78+84+72}{4} )+0.3 \times 78 +0.1 \times 86 + 0.2 \times 87 \\\\ W_m=  81.2 \%

Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.

To learn more about the mean refer;

brainly.com/question/22871228

#SPJ1

5 0
2 years ago
Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

1/cos^2x = 1 + sin^2x/cos^2x

<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
3 years ago
Read 2 more answers
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