Answer:
1.21 g of Tris
Explanation:
Our solution if made of a solute named Tris
Molecular weight of Tris is 121 g/mol
[Tris] = 100 mM
This is the concentration of solution:
(100 mmoles of Tris in 1 mL of solution) . 1000
Notice that mM = M . 1000 We convert from mM to M
100 mM . 1 M / 1000 mM = 0.1 M
M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris
0.1 M = mmoles of Tris / 100 mL
mmoles of Tris = 100 mL . 0.1 M → 10 mmoles
We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol
And now we determine the mass of solute, by molecular weight
0.010 mol . 121 g /mol = 1.21 g
Answer:
Moles of zinc chloride produced are 0.09942 moles.
Explanation:
Mass of zinc used = 6.5 g
Moles of zinc =
According to reaction, 1 mol of zinc gives 1 mole of zinc chloride,then 0.09942 moles of zinc will give :
of zinc chloride
Moles of zinc chloride produced are 0.09942 moles.
Answer:
Molecular formula = C₄H₁₂O₂
Explanation:
Given data:
Percentage of hydrogen = 13.80%
Percentage of carbon = 51.02%
Percentage of oxygen = 35.18%
Molecular formula = ?
Solution:
Number of gram atoms of H = 13.80 / 1.01 = 13.6
Number of gram atoms of O = 35.18 / 16 = 2.2
Number of gram atoms of C = 51.02 / 12 = 4.25
Atomic ratio:
C : H : O
4.25/2.2 : 13.6/2.2 : 2.2/2.2
2 : 6 : 1
C : H : O = 2 : 6 : 1
Empirical formula is C₂H₆O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = C₂H₆O = 46 g/mol
n = 88 / 46
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₂H₆O)
Molecular formula = C₄H₁₂O₂
If I'm correct buy all the formula and the work I did I'm coming up with 3.7%
