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leonid [27]
3 years ago
11

Gasoline contains only hydrogen and carbon atoms, yet nitrogen oxide and nitrogen dioxide are produced when gasoline burns. What

is the source of the nitro- gen and oxygen atoms?
Chemistry
2 answers:
White raven [17]3 years ago
7 0

Answer:

The answer to the question is

The source of the nitro- gen and oxygen atoms is from the atmosphere

Explanation:

When gasoline burns oxygen from the atmosphere supports the combustion reaction.

For example the internal combustion engine of a motor vehicle pulls in air from the surrounding atmosphere to make use of the oxygen in aiding the combustion of the gasoline to drive the pistons that ultimately moves the vehicle. The air from which the oxygen is absorbed also contains more amount of Nitrogen by percentage than oxygen. The nitrogen therefore enters into the combustion reaction that eventually produces nitrogen oxide and nitrogen dioxide

gregori [183]3 years ago
7 0

Explanation:

When fuels are burned either in vehicle engines or other processes, high temperatures are reached. At these high temperatures, nitrogen and oxygen from the air(which oxygen and nitrogen have significant percentages) combine to produce nitrogen monoxide. When this nitrogen monoxide is released from these systems, it combines with oxygen in the air to form nitrogen dioxide.

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Please Help!!!! Which of the following equations follows the Law of Conversation of Mass
Vladimir [108]
Option C. is correct

Calculate no. of each element on the reactant side and no. of elements on products side; If no. of elements in reactant = product,
then the reaction follows Law Conservation of Mass.
5 0
3 years ago
Photovoltaic cells convert solar energy into electricity. Calculate the wavelength of light (in nm) required for mercury (Φ =7.2
Sholpan [36]

Answer:

275.3 nm is the wavelength of light required for mercury.

Mercury can not be used to generate electricity from the sun because wavelength at which mercury will emit an electron is smaller than 500 nm.

Explanation:

The wavelength of light required for mercury  to emit an electron.

The wavelength of the radiation = \lambda

Energy required fro mercury to to emit an electron = E

Energy required fro mercury to to emit an electron will the energy if the radiation = E' = 7.22\times 10^{-19} J

E' = E

To calculate the wavelength of light, we use the equation:

E=\frac{hc}{\lambda }

where,

\lambda = wavelength of the light  

h = Planck's constant = 6.626\times 10^{-34} Js

c = speed of light = 3\times 10^8m/s

\lambda =\frac{hc}{E}

=\frac{6.626\times 10^{-34} Js\times 3\times 10^8m/s}{7.22\times 10^{-19} J}

\lambda =2.753\times 10^{-7} m=2.753\times 10^{-7}\times 10^ nm =275.3 nm

Wavelength of the sun light in the visible region = 500 nm

500 nm > 275.3 nm

E\propto \frac{1}{\lambda }

Less energy < more energy

So, this means that mercury can not be used to generate electricity from the sun.

6 0
3 years ago
The SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission proc
Vanyuwa [196]
To calculate the wavelength of this radiation if the SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the cesium atom, the wavelength is one cycle of radiation, and therefore the wavelength is 1/9192631770
8 0
3 years ago
Read 2 more answers
How would the pH value of an aqueous solution change, when the hydronium ion concentration is increased by a factor of 10?
Anna71 [15]

Answer:

Increasing H⁺ by 10x => pH decreases by 1 unit

Explanation:

In general, adding H⁺ ions to any aqueous solution ALWAYS causes pH values to fall ( decrease ). Just as adding OH⁻ ions to an aqueous solution causes pH values to rise ( increase ).

Here's a simple calculation demonstrating this...

Given 0.01M HCl(aq) => 0.01M H⁺(aq) + Cl⁻(aq) => pH = -log(0.01) = 2.00

Increase [H⁺] by 10x => 0.10M H⁺(aq) => pH = -log[H⁺] = -log(0.10) = 1.00

Solution with higher H⁺ concentration shows <u>pH decreasing by 1 unit.</u>

______________________________________________________-

Just to support the above statement about adding OH⁻ ions showing an increase in pH values, the following is also provided FYI ..

Given 0.01M NaOH(aq) => 0.01M OH⁻(aq) + Na⁺(aq) => pOH = -log(0.01) = 2.00 => pH = 14 - pOH = 14 - 2 = 12

Increase [OH⁻] by 10x => 0.10M OH⁻(aq) => pOH = -log[OH⁻] = -log(0.10) = 1.00 => pH = 14 - pOH = 14 - 1 = 13

Increasing [OH⁻] by 10x => <u>increasing pH by 1 unit. </u>

Solution with higher H⁺ concentration shows pH decreasing by 1 unit.

______________________________________________________

Remember, for <u>any</u> aqueous solution ...

=> Adding H⁺   => always decreases pH

=> Adding OH⁻ => always increases pH

4 0
3 years ago
High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie
kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically,  Molality = \frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = \frac{0.001002 g/L}{17 g/mol}

                        = 5.89 \times 10^{-4} mol/L

Also,    density = \frac{1 g}{mL} = 1 kg/L

Therefore, molality will be calculated as follows.

        Molality = \frac{5.89 \times 10^{-4} mol/L}{1 kg/L}

                      = 5.89 \times 10^{-4} mol/kg

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = \frac{0.000412 g/L}{46 g/mol}

                        = 8.956 \times 10^{-6} mol/L

And, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality = \frac{8.956 \times 10^{-6} mol/L}{1 kg/L}

                          = 8.956 \times 10^{-6} mol/kg  

Now, Molar mass of nitarte = 62 g/mol

      Concentration = 1352.2 mg/L

                              = \frac{1.3522 g/L}{62 g/mol}

                              = 0.02181 mol/L

Also, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality will be calculated as follows.

         Molality = \frac{0.02181 mol/L}{1 kg/L}

                       = 0.02181 mol/kg

Therefore, molality of given species is 5.89 \times 10^{-4} mol/kg  for ammonia, 8.956 \times 10^{-6} mol/kg  for nitrite, and 0.02181 mol/kg for nitrate ion.

7 0
3 years ago
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