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viva [34]
3 years ago
6

What is the [oh−] of a solution if its ph = 8.78? answer in units of m?

Chemistry
1 answer:
dexar [7]3 years ago
7 0
PH = -log([H+])
[H+] = 10^(-pH)

[H+] = 10^(-8.78) = 1.65*10^-9

[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.

[OH-] = Kw/[H+] = (1.0*10^-14)/(1.65*10^-9) = 6.06*10^-6

The concentration of OH- ions is 6.1*10^-6 M.
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Hello there!

In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:

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We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:

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Regards!

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