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3 years ago

What is the [oh−] of a solution if its ph = 8.78? answer in units of m?

1 answer:

7 0

PH = -log([H+])
[H+] = 10^(-pH)

[H+] = 10^(-8.78) = 1.65*10^-9

[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.

[OH-] = Kw/[H+] = (1.0*10^-14)/(1.65*10^-9) = 6.06*10^-6

The concentration of OH- ions is 6.1*10^-6 M.

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A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample i

mylen [45]

The sample of oxygen gas was collected through water displacement. So, the gas collected will be a mixture of oxygen and water vapor.

Given that the total pressure of the mixture of gases containing oxygen and water vapor = 749 Torr

Vapor pressure of pure water at $26.4^{0}C$ =25.81mmHg

= $25.81 mmHg*\frac{1 Torr}{1 mmHg} =25.81 Torr$

According to Dalton's law of partial pressures,

Total pressure = Partial pressure of Oxygen gas + Partial pressure of water

749 Torr = Partial pressure of Oxygen gas + 25.81 Torr

Partial pressure of Oxygen gas = 749 Torr - 25.81 Torr = 723.19 Torr

Therefore the partial pressure of Oxygen gas in the mixture collected will be 723.19 Torr

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3 years ago

A hydrate of zinc nitrate has the formula Zn(NO3)2 . xH2O. If the mass of 1 mol of anhydrous zinc nitrate is 63.67% of the mass

weqwewe [10]

MM Zn(NO₃)₂ = 189.36 g/mol

mass 1 mol Zn(NO₃)₂ = 189.36 g

mass hydrate = 100 / 63.67 x 189.36 = 297.409 g

mass 1 mol hydrate = 297.409 g

MM hydrate = 297.409 g/mol

MM hydrate = MM Zn(NO₃)₂ + MM xH₂O

297.409 = 189.36 + x(18)

x = 6

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2 years ago

The enzyme amylase will affect the breakdown of carbohydrates, but it will not affect the breakdown of proteins. The ability of

Alenkinab [10]

Answer:

Shape of the enzyme and its active site

Explanation:

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2 years ago

Gases present in atmosphere are in ionic form true or false

ANTONII [103]

Answer:

false

Explanation:

Only ionic compounds can dissolate in water.

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3 years ago

Graduated cylinder is filled to 41.5mL with water, and a price of granite is placed in the cylinder displacing the level to 47.6

Y_Kistochka [10]

Answer:

6.1 cm³

Explanation:

To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:

The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.

With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:

Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
Volume of the granite piece = 6.1 mL

Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.

8 0

3 years ago