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Sav [38]
2 years ago
5

b) Si los ácidos nitroso y fluorhídrico están descritos como electrolitos débiles, ¿significa que en la disolución hay moléculas

que no están disociadas?
Chemistry
1 answer:
viva [34]2 years ago
5 0

Los electrolitos son sustancias que se disocian en agua para dar iones.

Generalmente en química, podemos clasificar sustancias como

  • Electrolitos
  • No electrolitos

Los electrolitos pueden disociarse en solución para producir iones, pero un no electrolito no puede hacer eso.

Entre los electrolitos hay dos clases;

  • Electrolitos fuertes
  • Electrolitos débiles

Los electrolitos fuertes se disocian completamente en solución, mientras que los electrolitos débiles no se disocian completamente en solución.

El hecho de que los electrolitos débiles no se disocien por completo significa que algunas moléculas de la sustancia no se disocian.

Por lo tanto, si los ácidos nitroso y fluorhídrico se describen como electrolitos débiles, esto significa que hay moléculas en la solución que no están disociadas.

Lea más: brainly.com/question/14566383

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For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
3 years ago
______help in increasing rates of reactions
RideAnS [48]

Answer:

Catalysts help in increasing rates of reactions

4 0
3 years ago
Read 2 more answers
Which reactant will be the best reactant for a nucleophilic aromatic substitution?
tangare [24]

The reactant that will be the best reactant for a nucleophilic aromatic substitution is NO₂- NO₂. The correct option is b.

<h3>What is nucleophilic aromatic substitution?</h3>

Nucleophilic aromatic substitution is a substitution process of nucleophile substance is substituted by halides in an aromatic ring. Aromatic compounds contain this type of substitution.

In option b, the compound is the one nitroxide group substituted by halogen, that is fluorine. The fluorine group is substituted in these given aromatic compounds.

Thus, the correct option is b, NO₂- NO₂.

To learn more about nucleophilic aromatic substitution, refer to the link:

brainly.com/question/28265482

#SPJ4

The question is incomplete. Your most probably complete question is given below:

NO₂F

NO₂- NO₂-F

CH₃-O

CH₃-O-F

4 0
2 years ago
What is the molality of a solution containing 4.0 moles of solute in 3.2 kg of solvent? Round to the nearest tenth.
Cerrena [4.2K]

The formula for this is mol/kg = m. 4/3.2=1.25 m

5 0
4 years ago
What is the change in heat energy when 132g of copper at 32.2°C is raised to 45.0oC? The specific heat of copper is 0.385 J/g °C
Rudik [331]
Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as: 
<span>
Energy = mCΔT
</span><span>Energy = 132 (0.385) (45 - 32.2)
</span><span>Energy = 650.50 J</span>
4 0
3 years ago
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