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Wittaler [7]
3 years ago
6

In what type of radioactive decay does the atomic number of the product decrease by one? Select all that apply.

Chemistry
1 answer:
VladimirAG [237]3 years ago
4 0
The atomic number of the product decrease by one in the d) positron emission and the e) electron capture radioactive decay. These radioactive decays are two of three common forms of the Beta Decay which occurred when the proton released a positron and a neutron emitted an electron<span>. The Beta Decay can increase or decrease the atomic number.</span>
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Find the density of an object that has a mass of 6.13 g and volume of 1.50 cm³.​
storchak [24]
  • <em>Answer:</em>

<em>≈ 4.10 g/cm³</em>

  • <em>Explanation:</em>

<em>Hi there ! </em>

<em><u /></em>

<em><u>Density formula</u></em>

<em>d = m/V</em>

<em>d = 6.13g/1.5cm³</em>

<em>d = 4.08(6) g/cm³ ≈ 4.10 g/cm³</em>

<em />

<em>Good luck !</em>

8 0
3 years ago
Convert the following temperature to c 67k b) 1671k
kap26 [50]
  • Convert Kelvin to °c

(a) 67°c

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k=°c+273

°c = 273 - k

°c = 273-67= 206 °c

(b) 1671 k

k=°c+273

°c = 273 - k

°c= 273-1671 = -1398°c

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JulsSmile [24]

Answer:

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Explanation:

6 0
3 years ago
Read 2 more answers
A plate moves 200 m in 10,000 years. What is its rate in cm/year?
Varvara68 [4.7K]

Answer:

The answer is

<h2>2 cm/year</h2>

Explanation:

To find the rate in cm/year we must first convert 200 m into cm

1 m = 100 cm

if 1 m = 100 cm

Then 200 m = 200 × 100 = 20 ,000 cm

So the rate is

<h2>\frac{20000}{10000}</h2>

<u>Reduce the fraction with 10,000</u>

We have the final answer as

<h3>2 cm/year</h3>

Hope this helps you

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3 years ago
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Answer:

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3 years ago
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