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leonid [27]
3 years ago
14

What is the molality of a solution containing 125 grams of iodine (I2) and 750 grams of CCl4? A. 1.2 m. . B. 6.57 m. . C. 0.657

m. . D. 0.12 m.
Chemistry
1 answer:
uysha [10]3 years ago
4 0
The answer is <span>C. 0.657 m.
</span>
The molality is the number of moles of solute divided by kilograms of solvent. In a solution, solute the component which is present in lesser amount while solvent is present in greater amount. Thus, I2 is solute, and CCl4 is solvent.

So, first we need to calculate moles of I2:
Atomic mass of iodine: A(I) = 126.9
Molecular mass of iodine: Mr(I2) = 2*A(I) = 2 * 126.9 = 253.8
This means there are 253.8 g of iodine in 1 mole. So, 125 g of iodine will be in how many moles?
253.8 : 1 = 125 : x         ⇒      x = 125/253.8 = 0.493 moles

Now, let's convert amount of CCl4 in kilograms (1 kg = 1000 g):
750 g = 750/1000 kg = 0.75 kg

And now, it's only left to calculate molality of the solution:
numbers of moles of solute/kilograms of solvent = 0.493 moles/0.75 kg = 0.657 m
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3 years ago
A gas that was heated to 150 Celsius has a new volume of 1587.4 L. What was its volume when its temperature was 100 Celsius?
sdas [7]

Answer:

\boxed {\boxed {\sf 1058.3 \ L}}

Explanation:

We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

\frac {V_1}{T_1}= \frac{V_2}{T_2}

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{T_2}

The temperature was 100 degrees Celsius, but the volume is unknown.

\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C}

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.

100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C} * 100 \textdegree C

100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = V_2

The units of degrees Celsius cancel.

100  *\frac {1587.4 \ L }{150 } = V_2

100 *10.58266667  \ L = V_2

1058.266667 \ L = V_2

The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

1058.3 \ L = V_2

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>

6 0
3 years ago
How many grams of oxygen can be produced from the decomposition of 100. g of kclo3?
aivan3 [116]
<span>100 g of KClO3 @ 122.55 g/mol = 0.816 moles of KClO3
   by the reaction
 2 KClO3 --> 2 KCl & 3 O2

   0.816 moles of KClO3 @ 3 moles O2 / 2 moles KClO3 = 1.224 moles of O2 can be made using molar mass
 1.224 moles of O2 @ 32.0 g/mol =
 39.2 grams of O2 can be made</span>
6 0
3 years ago
Read 2 more answers
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