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3 years ago

What decimal is equal to 270%

Mathematics

2 answers:

marusya05 [52]3 years ago

8 0

The answer would be 2.7

Papessa [141]3 years ago

4 0

Answer:2.7

Step-by-step explanation:

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The triangular entrance to a tent is 2/3 as wide as it is tall. The area of the entrance is 12ft^2. Find the height and the base

Reika [66]

X+ $\frac{2}{3} x$ =12
5x=36
x=7.2
So, the triangular entrance to the tent is 7.2 feet tall and 4.8 feet wide

4 0

3 years ago

The relationship between angles a and b?

Rina8888 [55]

Answer:

They are both acute angles

7 0

2 years ago

Read 2 more answers

I WILL MARK THE BRAINIEST!!!!!!! WRONG ANSWER'S WILL BE REPORTED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

trasher [3.6K]

The correct answer should be choice A

5 0

2 years ago

Assume that the helium porosity of coal samples taken from any particular seam is Normally distributed with true standard deviat

riadik2000 [5.3K]

Answer:

a) $4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

b) $4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

c) $n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

Part b

$4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.4/2 =0.2 we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

5 0

3 years ago

Find the area of this triangle. Round to the nearest tenth. ASAP PLEASE.

Sati [7]

Answer:

the answer is 60.0

Step-by-step explanation:

28.8+12+18=58.8

rounded to the nearest 10th would be 60.0

8 0

3 years ago