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Hitman42 [59]
2 years ago
10

A large bottle of Sharkleberry Finn juice contains 600 milliliters of juice. A medium bottle contains 70% as much juice as the l

arge bottle. Draw this number line on a separate piece of paper and fill in the missing numbers. juice (ml) 1006 How many milliliters of juice should be represented in the box that corresponds with 100%?​
Mathematics
1 answer:
12345 [234]2 years ago
7 0

Answer:

dss

Step-by-step explanation:

sds

sd

s

ds

d

as

d

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Simplify X 1/2 times X 2/3
vovikov84 [41]

Answer:

3/6x • 4/6x

12/6x

2x

Step-by-step explanation:

you would change both fractions to have the same denominator then simplify if needed

5 0
2 years ago
Simplify the expression to a+bi form: (10+10i)+(-7+3i)
Greeley [361]

Answer:

3+13i

Step-by-step explanation:

(10+10i)+(-7+3i)

Combine the real parts

10+-7 = 3

And the imaginary parts

10i +3i = 13i

Combine them to make the complex number

3+13i

3 0
3 years ago
Evaluate the expression 3.14(a2 + ab) when a = 4 and b = 3. (Input decimals only, such as 12.71, as the answer.)
sveta [45]

Answer:

87.92

Step-by-step explanation:

3.14(a² + ab)

= 3.14 (4² + 4 × 3)

= 3.14 (16 + 12)

= 3.14 × 28

= 87.92

Hope it helps :)

Please mark my answer as the brainliest

3 0
2 years ago
Read 2 more answers
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
frosja888 [35]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

8 1
3 years ago
Which account has the highest effective annual interest rate? Account 1: Interest is compounded quarterly at an annual rate of 4
LenKa [72]

Answer:

Account 1 has the highest effective annual interest rate (0.042666142)

Step-by-step explanation:

Hi, to answer this question we have to apply the Effective Annual Interest Rate formula:  

EAIR = [(1+r/n)^n ]-1

Where:

r = nominal interest rate

n = number of periods

If interest is compounded annually, then n = 1; if semi-annually, then n = 2; quarterly, then n = 4; monthly, then n = 12

SO:

Account 1: Interest is compounded quarterly at an annual rate of 4.20%.  

EAIR = [(1+r/n)^n ]-1 = [(1+(4.20/100)/4)^4 ]-1 = 0.042666142

Account 2: Interest is compounded monthly at an annual rate of 4.15%.  

EAIR = [(1+r/n)^n ]-1 = [(1+(4.15/100)/12)^12 ]-1 =0.042298535

Account 3: Interest is compounded semiannually at an annual rate of 4.10%

EAIR = [(1+r/n)^n ]-1 = [(1+(4.10/100)/2)^2]-1 = 0.04142025

Account 4: Interest is compounded annually at a rate of 4.25%.

EAIR = [(1+r/n)^n ]-1 = [(1+(4.25/100)/1)^1 ]-1 = 0.0425

Since:

0.042666142 (1) < 0.0425 (4) < 0.042298535(2) <0.041420258(3)

Account 1 has the highest effective annual interest rate 0.042666142

7 0
3 years ago
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