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3 years ago

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Answer these questions in order

1 answer:

mash [69]3 years ago

4 0

1)-6/4x+4

2)-5/3x

3)3x+2

4)3/2x+3

5)0x-1

6)1/2x+2

7)3x+4

8)-1/3x

I added some guides for you to know how to do this.

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A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n

ki77a [65]

Answer:

a)

i. x=- - - - - -

ii. o=- - - - - -

iii. Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.

c) The statistics variable X is a measure on a sample that is used as an estimate of the population mean.X is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters because the population standard deviation is known.

N(X, o/ $\sqrt{n}$ )

So, the distribution is

N(2, 0.12/ $\sqrt{16}$ )

e)

i. The 90% confidence interval for the population mean weight of the candies is 1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is 1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

a)

i. x=- - - - - -

ii. o=- - - - - -

iii. Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.

c) The statistics variable X is a measure on a sample that is used as an estimate of the population mean.X is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters because the population standard deviation is known.

N(X, o/ $\sqrt{n}$ )

So, the distribution is

N(2, 0.12/ $\sqrt{16}$ )

e)

i. The 90% confidence interval for the population mean weight of the candies is 1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is 1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0

3 years ago

Simplify the complex number. Express your answer in a + bi form and include each step necessary in simplifying.<img src="https:/

insens350 [35]

$\dfrac{x+iy}{u+iv}\times\dfrac{u-iv}{u-iv}=\dfrac{(x+iy)(u-iv)}{u^2-(iv)^2}$
$=\dfrac{xu-i^2yv+iyu-ixv}{u^2+v^2}$
$=\underbrace{\dfrac{xu+yv}{u^2+v^2}}_a+i\underbrace{\dfrac{yu-xv}{u^2+v^2}}_b$

3 0

4 years ago

Does anyone know c & d please

Afina-wow [57]

Subtract the powers
c. 9-7 so 10^2
d. 8-1 so 5^7

7 0

3 years ago

Read 2 more answers

A clothing store sold 4 times as many sweaters as coats. The difference in the sales was 300. How many of each were sold?

slava [35]

Sweater = 400
coats = 100
difference= 300
in an equation it would be
4x-x=300
so
3x=300
x=100
sweaters= 4x= 400
coats= x= 100

5 0

3 years ago

Anna truncated the decimal expansion of x to find the best approximation. On a number line, the location of x is between 10.9 an

podryga [215]

Answer:

Well to estimate a decimal the best option would be to round it to.

10 or 11 (For 10.9)

11 (For 11.1)

and since two of them equal 11.

The estimation would be 11.

I hoped this helped.

3 0

3 years ago