Question

Which of the following best explains how this relationship and the value of sin theta can be used to find the other trigonometric values?

Answer 1

Answer:

OPtion I is right

Step-by-step explanation:

Once we know sin of an angle, and it lies in II quadrant, we know that

cos, sec, tan and cot would be negative but csc will be positive.

So use the fact that

$sin^{2}t+cos^{2} t=1\\cost =-\sqrt{1-sin^2 t}$

Thus cos is obtained using negative square root.

Now tan = sin/cos, and sec = 1/cos:

cot =1/tan and csc =1/sin

Thus all value can be obtained easily

So option I