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zubka84 [21]
3 years ago
11

What’s the correct answer for this question?

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

Arc length : In his pizza, Arc length is the outer boundary of pizza and it can be calculated if we know the side length of the pizza and the central angle

Area of sector: since the whole pizza piece is a sector hence to calculate it's area we can use the formula of area of sector

(In degrees) = m/360 (πr²)

(In radians) = 1/2r²∅(theta)

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Find the length of the longest side of the rectangle whose vertices are given. a(2, 1), b(5, 4), c(0, 3), d(3, 6)
aleksandr82 [10.1K]
First, you plot the coordinates to visualize the problem clearly. As you can see in the picture, the longest sides could either be one of those marked in red. This could be initially determined when you use visual estimation. We measure this using the distance formula: d = √[(x2-x1)^2 + (y2-y1)^2)]

Between coordinates (0,3) and (3,6)
d = √[(3-0)^2 + (6-3)^2)]
d= 4.24 units

Between coordinates (2,1) and (5,4)
d = √[(5-2)^2 + (4-1)^2)]
d= 4.24 units

They are of equal length. Both are the longest sides which measures 4.24 units.

5 0
2 years ago
What are the coordinates of B if (5,3) is 1/3 of the way from A to B
LenaWriter [7]

The coordinates would be 4,0?

7 0
2 years ago
Factor 15x + 35 using the GCF
Sedaia [141]

Answer:

Step-by-step explanation:

find all of tehe factors to both numbers

15x = 5 3 x

35 = 5 7

pull 5 out of both of them and put the remaining factors in parentheses

5(3x + 7)

8 0
2 years ago
A rectangle has an area of 30 square meters and a perimeter of 34 meter. What are the dimensions of the rectangle?
Veseljchak [2.6K]
Rectangle's Perimeter is P=2(w+l)
where w and l are width and length respectively
34=2(w+l)
17=w+l
w=17-l

now A=wxl
A=(17-l)xl
A=17l-l^2
30=17l-l^2
l^2-17l-30=0

now solve for l



8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28W%5E%7B8%7D%20%29%5E%7B8%7D" id="TexFormula1" title="(W^{8} )^{8}" alt="(W^{8} )^{8}" align
MaRussiya [10]

Answer:

<h2>w^64</h2>

Step-by-step explanation:

\left(w^8\right)^8\\

\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc}

\left(w^8\right)^8=w^{8\times\:8}\\=w^6^4

4 0
3 years ago
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