12(2)+5
Dang, you're an elementary school er? Good grief i'm and 8th grade math one student!
Answer:
Step-by-step explanation:
Let x represent the cost of one white chocolate pretzel.
Let y represent the cost of one dark chocolate pretzel.
Rico bought 4 white chocolate pretzels and 6 dark chocolate pretzels for $10.50. This means that
4x + 6y = 10.5 - - - - - - - - - - -1
Holden bought 8 white chocolate and 3 dark chocolate pretzels for $9.75. This means that
8x + 3y = 9.75 - - - - - - - - - 2
Multiplying equation 1 by 8 and equation 2 by 4, it becomes
32x + 48y = 84
32x + 12y = 39
Subtracting, it becomes
36y = 45
y = 45/36 = $1.25
Substituting y = 1.25 into equation 1, it becomes
4x + 6 × 1.25 = 10.5
4x + 7.5 = 10.5
4x = 10.5 - 7.5 = 3
x = 3/4 = $0.75
the total cost for 6 white chocolate pretzels and one dark chocolate pretzel would be
6 × 0.75 + 1 × 1.25 = 4.5 + 1.25 = $5.75
24 of the 360 students are likely to win a prize.
There is a 1/15 chance of winning a prize.
Let c=cost of chicken and d=cost of duck; 50c+30d=550 and 44c+36d=532.
So 5c+3d=55, 11c+9d=133.
Therefore 15c+9d=165, subtracting 11c+9d=133 we get: 4c=32 so c=8.
5c+3d=40+3d=55, so 3d=15 and d=5.
Cost of chicken is $8 and cost of duck is $5.
