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dmitriy555 [2]
3 years ago
7

1. After quarantine is over, you and your family are planning to rent a van for a 1-day trip to Knott’s Berry Farm in Buena Park

, CA. For the type of van, your family would like to rent, you can choose from the following options:
• Enterprise Rent-A-Car: $50 per day and $0.25 a mile

• Alamo Car Rental: $45 per day and $0.35 a mile

• Budget Car Rental: $40 per day and $0.30 a mile

• Hertz Car Rental: $30 per day and $0.45 a mile

• Thrifty Car Rental: $35 per day and $0.50 a mile


(a) Choose two of the car rental companies above that you would like to compare prices for and write a mathematical model to represent the cost of renting a van from the two companies.


Rental Company Choice Mathematical Model

A.

B.



(b) Graph these mathematical models in each blank graph provided on the next page. Make sure your model A matches graph A and your model B matches graph B. Please label the graph axes appropriately.

Mathematics
1 answer:
kupik [55]3 years ago
3 0

9514 1404 393

Answer:

  A) Enterprise: E(x) = 50 +0.25x; Hertz: H(x) = 30 +0.45x

  B) see attached graph

Step-by-step explanation:

A) We choose to compare Hertz (lowest daily charge) and Enterprise (lowest mileage charge). In each case, the total charge will be the sum of the daily charge and the product of the mileage charge and number of miles (x).

  Enterprise: E(x) = 50 +0.25x

  Hertz: H(x) = 30 +0.45x

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1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
Solve for k 4.5+1.5k=18−3k
sertanlavr [38]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{k = 3}}}}}

Step-by-step explanation:

\sf{4.5 + 1.5k = 18 - 3k}

Move 3k to left hand side and change it's sign

Similarly, move 4.5 to right hand side and change it's sign

\longrightarrow{ \sf{1.5k + 3k = 18 - 4.5}}

Collect like terms

\longrightarrow{ \sf{4.5k = 18 -  4.5}}

Subtract 4.5 from 18

\longrightarrow{ \sf{4.5k = 13.5}}

Divide both sides by 4.5

\longrightarrow{ \sf{ \frac{4.5k}{4.5}  =  \frac{13.5}{4.5} }}

Calculate

\longrightarrow{ \sf{k = 3}}

Hope I helped!

Best regards! :D

5 0
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Len [333]

Answer:

35/30

Step-by-step explanation:

4 0
2 years ago
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8 0
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State the property that justifies the statement: If 4x + 9 = 15 and X=2y + 1,
GREYUIT [131]

Answer:

Substitution property of equality

Step-by-step explanation:

Given

4x + 9 = 15 and x = 2y + 1

Then

4(2y + 1) + 9 = 15

Required

State the property

From the list of options, (d) answers the question.

This is so because:

Substitution property of equality states that

If a = b then b = a

In other words, both can replace one another.

So if x = 2y + 1, then 2y + 1 can be substituted for x in 4x + 9 = 15

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4x + 9 = 15  becomes

4(2y + 1) + 9 = 15

<em>Hence, it is substitution property of equality</em>

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