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Basile [38]
3 years ago
15

mason is an architect and is drawing plans for a room addition for a client if the shape of the cube what is the volume in cubic

feet is the length is 23 feet
Mathematics
1 answer:
Alex777 [14]3 years ago
8 0
Well if the room is going to be cubed and the length of one side is 23 whenever you want to find the volume of a cube all you do is take one side and square it.
so we have 23² which equals 529 
the volume would be 529 cubic feet 
hope this helps
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Chloe wants to buy monitor for her bedroom the height of the monitor is 18 inches in the width is 16 inches calculate the diagon
Akimi4 [234]
Equation: a^2 + b^2 = c^2

18^2 + 16^2 = c^2

324 + 256 = c^2

C^2 = square root 580

Square root 580 reduces to 2 square root 145.

As a decimal that is: 24.08

Rounded to the nearest tenth: 24 inches.

I hope this helps! If it does please offer me the brainiest!
3 0
3 years ago
FACTOR the TRINOMIAL 2p^2-7p+8.
boyakko [2]

You can not factor this .

It's impossible to factor this .


I hope that's help !

7 0
3 years ago
SOMEONE ANSWER THESE PLEASE!!
Svetradugi [14.3K]
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7 0
3 years ago
The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
3 years ago
3. WHAT IS THE END BEHAVIOR?SHOW WORK.<br><br> - 10x -x+ 2
nekit [7.7K]

Answer:

Step-by-step explanatio

−10x−x+2

=−10x+−x+2

=−10x+−x+2

=(−10x+−x)+(2)

=−11x+2

Answer:

=−11x+2

 

3 0
3 years ago
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